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3 years ago

0.16+0.45 eaqkesbnnn

2 answers:

4 0

Sorry, but I have no idea what your "eaqkesbnnn" means.

If you were supposed to add 0.16 and 0.45, the correct answer would be 0.61.

Nutka1998 [239]3 years ago

4 0

Hello there, and thank you for asking your question here on brainly.

Short answer: 0.61 || 61/100

Why?

When you're adding two decimals, as long as it doesn't have a whole number, you can just add down like so.
1
0.16
+ 0.45
_______
0.61
In fraction form, it is 61/100, because we have the decimal number, and put it to how long it is. (hundred[th])

Hope this helped you! ♥

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Divide 72 rolls into 2 groups so the ratio is 3 to 5.

madam [21]

$3x\ and \ 5x\\\\
3x+5x=72\\
8x=72\ \ \ |divide\ by\ 8\\x=9\\\\
3x=3*9=27\\
5x=5*9=45\\\\
Ratio\ of\ rolls:\ \ 27:45.$

3 0

3 years ago

Read 2 more answers

The museum charges $14 for adult admission and $11 for each child. the museum bill for a school field trip was $896.

lord [1]

14x + 11y = 896

x = number of adults
y= number of kids
if nine adults went then 70 kids went

6 0

3 years ago

What is the solution to this system of equations

statuscvo [17]

The answer to the question is b

6 0

3 years ago

Find the value of x in the triangle shown below

JulijaS [17]

Answer:

x = 3

Step-by-step explanation:

we can use the Pythagorean theorem to solve this problem

x^2 + 4^2 = 5^2

x^2 + 16 = 25

x^2 = 9

x = +/- 3

we take only the positive value because a length can‘t be negative

x = 3

5 0

3 years ago

Poker. 26 red, 26 black. Take one every time, you can choose to guess whether it’s red. You have only one chance. If you are rig

xenn [34]

Answer: 339/8788= 0.039

Step-by-step explanation:

Let black card be represented with B and the red card be represented with r. Therefore, P(B,r) is the expected value.

Hence, we say, (b,r) is not equal to (0,0) for the first state, we then, have a probability of B/r+B(the probability of drawing out a black card and loosing a point.

Also, (B-1,r) state with the probability of r/r+B(which is the probability of drawing out a red card and gaining a point).

The expected value is therefore;

B/r+B(-1+(B-1,r) + r/r+B(1+P(B,r-1))

Therefore, if we have negative, then;

P(B,r)=0,B/r+B(-1,r)) + r/r+B(1+P(B,r-1))...

P(0,0)=0; P(26,26) = 339/8788

=.039

Note: we say that the expectation at the start if we draw red,gaining +1 and if we draw black and then draw two reds you end +1. That is; 1/26 × 2/26 × 1/26 = 1+ 338/8788

= 339/8788.

5 0

3 years ago