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Natasha2012 [34]
3 years ago
12

The space shuttle is located exactly half way between the earth and the moon. Which statement is true regarding the gravitationa

l pull on the shuttle? A) The moon pulls more on the shuttle. B) The earth pulls more on the shuttle. C) Both are equal due to equal distances. D) Both are equal due to the mass of the shuttle.
Physics
2 answers:
lianna [129]3 years ago
4 0

B

The earth is larger (approximately 6 times larger) than the moon hence it will have a stronger gravitational pull on the shuttle than the moon has on the shuttle. Because the shuttle is halfway between the moon and earth, the influence of distance in the gravity formula between the two is negated.

Explanation:

Gravitation force depends on distance and mass of objects in the universe. The bigger the mass of an object the higher its gravitational pull while the shorter the distance between the objects the higher the gravitaiton pull between the two. This phenomenon is described by the formulae below;

F = G (M1 – M2) / r2

Where;

F = gravitational force

G = Gravitational constant

M1 = mass of the first object

M2 = mas of the second object

R = distance between the two objects

Learn More:

For more on gravity check out;

brainly.com/question/9934704

brainly.com/question/13418722

#LearnWithBrainly

11111nata11111 [884]3 years ago
3 0
B. The mass of the earth is much greater than that of the moon, and therefore since it is the same distance between the moon and the earth the gravitational pull from the earth is stronger than that of the moon.
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A 2,537-kg truck moving at 14 m/s strikes a car waiting at a traffic light, hooking bumpers. The two continue to move together a
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Answer:

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Explanation:

From Law of conservation of momentum,

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m₂ = (m₁V - m₁u₁)/(u₂-V)..................... Equation 2

Where m₁ = mass of the truck, m₂ = mass of the car, u₁ initial velocity of the truck, u₂ = initial velocity of the car V = common velocity

Given: m₁ = 2537 kg, u₁ = 14, V= 8 m/s, u₂ = 0 m/s ( as the car was at rest waiting at a traffic light)

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3 years ago
An object in space is initially stationary relative to the Earth. Then, a force begins acting on the object, starting with a for
11111nata11111 [884]

Answer:

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Explanation:

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From the given data

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630 = 10 x (v_f - 0)

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