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4 years ago

Decimals between 10 15 with an interval of 0.75 between each pair of decimals

Mathematics

1 answer:

OleMash [197]4 years ago

8 0

Need a little more what the ?

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James needs to clock in a minimum of 9 hours per day at work. However, the working hours that he records varies between 9 to 12

Sergio [31]

The median is 0 I think and I'm sorry I don't know about the skew of the distribution

5 0

4 years ago

Solve for X ??? A. 2 / 15 B. 20 C. 30 D. / 35

Finger [1]

Answer:

2 sqrt(15)

Step-by-step explanation:

Using the secant tangent formula

(whole secant) x (external part) = (tangent)^2

(5+7) * 5 = x^2

12*5 = x^2

60 = x^2

Taking the square root

sqrt(60) = sqrt(x^2)

sqrt(4*15) = x

2 sqrt(15) =x

6 0

3 years ago

2dollars and 25Cents 9 times what the Total is

abruzzese [7]

Answer:

$20.25

Step-by-step explanation:

2.00 +.25=2.25

2.25*9= 20.25

7 0

3 years ago

You are watering a garden. The height h (in feet) of water spraying from the garden hose can be modeled by h(x)=−0.1x2+0.7x+3, w

swat32

Answer:

$g(x) = -0.1x^2 + 0.5x + 3.6$

Step-by-step explanation:

Given

$h(x) = -0.1x^2 + 0.7x + 3$

Required

Determine the new function

From the question, we understand that the new function wants the water to hit the ground 1 ft farther.

1 ft farther implies x + 1

So, in the given function, we substitute x + 1 for x in $h(x) = -0.1x^2 + 0.7x + 3$

This gives:

$h(x + 1) = -0.1(x + 1)^2 + 0.7(x + 1) + 3$

Expand Bracket

$h(x + 1) = -0.1(x + 1)(x + 1) + 0.7(x + 1) + 3$

$h(x + 1) = -0.1(x^2+2x+1) + 0.7(x + 1) + 3$

$h(x + 1) = -0.1x^2-0.2x-0.1 + 0.7x + 0.7 + 3$

Collect Like Terms

$h(x + 1) = -0.1x^2-0.2x + 0.7x + 0.7 + 3-0.1$

$h(x + 1) = -0.1x^2 + 0.5x + 3.6$

Hence, the new function is:

$g(x) = h(x + 1) = -0.1x^2 + 0.5x + 3.6$

$g(x) = -0.1x^2 + 0.5x + 3.6$

3 0

3 years ago

What is the number sentence for "1 less than N is the sum of Z and 2"?

Katen [24]

Answer:

N–1=Z+2 should be the solution.

4 0

2 years ago