Complete Question
The complete question is shown on the first and second uploaded image
Answer:
The velocity is
Explanation:
The kinetic energy of the 9 kg can be determined by these expression
Kinetic energy of 9 kg block = initial energy stored - energy lost as a result of friction
Now to obtain the initial energy stored
Let U denote the initial energy stored and

Where x is the length the spring is displaced
k is the force constant of the string


Now referring to the formula above
i.e Kinetic energy of 9 kg block = initial energy stored - energy lost as a result of friction



and we are told that coefficient of friction = 0.4 and the mass is 9 kg ,the acceleration due to gravity
this displacement length of spring = 0.6
Therefore 
Answer:
F = 84.61 N
Explanation:
As in the figure, since there is no friction so if component of Force applied along the incline is greater than the component of weight along the incline, then the object will move up the incline.
component of Force along the incline = F cos(23° - 15°) = F cos(8°)
component of weight along the incline = 33*g*sin(15°) = 33*9.81*sin(15°)
Equating the above two components of forces will give the minimum Force required.
F cos(8°) = 33*9.81*sin(15°)
F = 33*9.81*sin(15°) / cos(8°) (calculate the value using a scientific calculator)
<u>F = 84.61 N</u>
Answer:
The mass of 20 cm of the metal is 360 grams.
Explanation:
Relative density or specific gravity is the ratio of the density of a substance to the density of a standard; usually water for a liquid or solid, and air for a gas. It has no units.
Given, relative density of a metal is 19 and volume of the metal is 20 cm.
We know that, Mass= Volume X Density. So, mass is 19 X 20= 380 grams.
So, weight in water = true weight- upthrust
Desired answer is 380- 20 X 1= 360 grams.
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