All categories

3 years ago

A box of cleaning supplies weighs 15 N. If the box is lifted a distance of 0.60 m, how much work is done?

Chemistry

2 answers:

VikaD [51]3 years ago

6 0

Answer:

Work done = 9 Joules

Explanation:

Work is done when a force applied to an object causes a displacement. When a force applied to an object causes a distance , work is said to be done . Example A woman pushing a cart in a shopping mall. Work is done because force is applied by the woman and it causes the object(cart) to move a distance. The S.I unit of work is joules.

Work can be represented mathematically as

Work = force × displacement

Force = 15 N

distance = 0.60 m

W = F × d

W = 15 × 0.60

Work done = 9 Joules

Note that weight is a force and is defined as the force exerted on a body.

Nady [450]3 years ago

3 0

Work Done = force x displacement. So in this case the 15N is the force (because weight is a force) and 0.60m is the displacement. Therefore 15 x 0.6 = 9 Joules of work done (btw, work done can also be referred to as energy transferred)

You might be interested in

The equilibrium constant for the formation of ammonia from nitrogen and hydrogen is 1.6 × 102. what is the form of the equilibri

Nimfa-mama [501]

Answer: The expression for equilibrium constant is $\frac{[NH_3]^2}{[H_2]^3[N_2]}$

Explanation: Equilibrium constant is the expression which relates the concentration of products and reactants preset at equilibrium at constant temperature. It is represented as $k_c$

For a general reaction:

$aA+bB\rightleftharpoons cC+dD$

The equilibrium constant is written as:

$k_c=\frac{[C]^c[D]^d}{[A]^a[B]^b}$

Chemical reaction for the formation of ammonia is:

$N_2+3H_3\rightleftharpoons 2NH_3$

$k_c=1.6\times 10^2$

Expression for $k_c$ is:

$k_c=\frac{[NH_3]^2}{[H_2]^3[N_2]}$

$1.6\times 10^2=\frac{[NH_3]^2}{[H_2]^3[N_2]}$

8 0

3 years ago

In a titration of 47.41 mL of 0.3764 M ammonia with 0.3838 M aqueous nitric acid, what is the pH of the solution when 47.41 mL +

Volgvan

Answer: The pH of the solution is 1.136

Explanation:

To calculate the moles from molarity, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}$

For ammonia:

Molarity of ammonia = 0.3764 M

Volume of ammonia = 47.41 mL = 0.04741 L (Conversion factor: 1 L = 1000 mL)

Putting values in above equation, we get:

$0.3764mol/L=\frac{\text{Moles of ammonia}}{0.04741L}\\\\\text{Moles of ammonia}=0.01784mol$

For nitric acid:

Molarity of nitric acid = 0.3838 M

Volume of ammonia = (47.41 + 10.00) mL = 57.41 mL= 0.05741 L

Putting values in above equation, we get:

$0.3838mol/L=\frac{\text{Moles of nitric acid}}{0.05741L}\\\\\text{Moles of nitric acid}=0.02203mol$

After the completion of reaction, amount of nitric acid remained = 0.022 - 0.0178 = 0.0042 mol

For the reaction of ammonia with nitric acid, the equation follows:

$NH_3+HNO_3\rightarrow NH_4NO_3$

At $t=0$ 0.0178 0.022

Completion 0 0.0042 0.0178

As, the solution of the reaction is made from strong acid which is nitric acid and the conjugate acid of weak base which is ammonia. So, the pH of the reaction will be based totally on the concentration of nitric acid.

To calculate the pH of the reaction, we use the equation:

$pH=-\log[H^+]$

where,

$[H^+]=\frac{0.0042mol}{0.05741L}=0.0731M$

Putting values in above equation, we get:

$pH=-\log(0.0731)\\\\pH=1.136$

Hence, the pH of the solution is 1.136

8 0

3 years ago

What is the molarity of a solution composed

Neporo4naja [7]

Answer:

0.0845 M

Explanation:

First we convert 4.27 grams of potassium iodide into moles, using its molar mass:

Molar Mass of KI = 166 g/mol

4.27 g ÷ 166 g/mol = 0.0257 mol

Now we calculate the molarity of the solution, using the number of moles and the given volume:

Molarity = moles / liters

Molarity = 0.0257 mol / 0.304 L = 0.0845 M

7 0

3 years ago

PLEASE HELP ME WITH MY CHEM TEST

fgiga [73]

Answer:

8. 0.96

9. d

10b

11. 3

12 d

Explanation:

4 0

3 years ago

How many moles are in 2.6 x 10 ^25 atoms of Li?

Cerrena [4.2K]

Answer:

43 mole

Explanation:

Given data:

Number of atoms of Li = 2.6× 10²⁵ atoms

Number of moles = ?

Solution:

The given problem will solve by using Avogadro number.

It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance. The number 6.022 × 10²³ is called Avogadro number.

1 mole = 6.022 × 10²³ atoms

2.6× 10²⁵ atoms × 1 mole / 6.022 × 10²³ atoms

0.43 × 10² mole

43 mole

5 0

3 years ago