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Ganezh [65]
3 years ago
12

What is a way in which nuclear fusion is used?

Chemistry
1 answer:
Marta_Voda [28]3 years ago
3 0

Answer:It is a nuclear process, where energy is produced by smashing together light atoms. It is the opposite reaction of fission, where heavy isotopes are split apart.

Explanation Fusion is the process by which the sun and other stars generate light and heat.

It’s most easily achieved on Earth by combining two isotopes of hydrogen: deuterium and tritium. Hydrogen is the lightest of all the elements, being made up of a single proton and a electron. Deuterium has an extra neutron in its nucleus; it can replace one of the hydrogen atoms in H20 to make what is called “heavy water.”

You might be interested in
(a) Calculate the energy released by the alpha decay of 222 86Rn.
Alinara [238K]

Answer:

a). The energy released by the alpha decay of 222 Rn is to 218 Po :

= 5.596 MeV

b).The energy of the alpha particle is 5.5 MeV

c) The recoil energy of Po = 0.096 MeV

Explanation:

The equation for the alpha decay of Rn to Polonium is:

_{86}^{222}\textrm{Rn}\rightarrow _{2}^{4}\textrm{He}+_{84}^{218}\textrm{Po}

The energy of the decay process can be calculated using:

\Delta E=\Delta mc^{2}

\Delta m = Change in the mass

Mass of Po = 218.008965 u

Mass of He = 4.002603 u

Mass of Rn = 222.017576 u

\Delta m = mass of Po + mass of He - mass of Rn

=  4.002603 + 218.008965-222.017576  

= - 0.006008

\Delta E=m(931.5MeV)

\Delta E=-0.006008\times 931.5MeV

= -5.596 MeV

<u><em>The negative sign means energy is released during the process.</em></u>

b) The energy of the alpha particle is :

\frac{Po\ mass }{Rn\ mass}\times E

\frac{218.0089}{222.0175}\times \Delta E

\frac{218.0089}{222.0175}\times 5.596

= 5.494 MeV

= 5.5 MeV

c).

Recoil energy: When the parent nucleus is at rest before the decay then , there must be the some recoil of daughter nucleus to conserve the momentum.This is termed as recoil energy.

<u><em>The energy of the recoil polonium atom :</em></u>

The formula for recoil energy is :

<em>The total energy - the kinetic energy</em>

<em>= 5.596 - 5.5 </em>

<em>= 0.096 MeV</em>

7 0
3 years ago
Every element has a unique amount of
tamaranim1 [39]
Protons is the answer
5 0
2 years ago
The point in a titration at which the indicator changes is called the
irakobra [83]

Answer:

End point

Explanation:

The point at which the indicator changes color is called the endpoint. So the addition of an indicator to the analyte solution helps us to visually spot the equivalence point in an acid-base titration

#correct me if I'm wrong

keep safe and study hard

brainliest please thank you

8 0
2 years ago
If mercury (Hg) and oxygen (O2) were reacted to form mercury oxide how many molecules of each reactant and product would be need
dimulka [17.4K]
In order to get HgO you would need 2Hg+1O2=2HgO. Since oxygen is diatomic you need two when it stands alone causing you to need two mercuries to balance out the reactants and the product I hope this helps
5 0
3 years ago
What mass of iron is needed to react with sulfur in order to produce 96 grams of
fiasKO [112]

Answer:

51.69 g of Fe

Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated below:

2Fe + 3S —> Fe₂S₃

Next, we shall determine the mass of Fe that reacted and the mass of Fe₂S₃ produced from the balanced equation. This can be obtained as follow:

Molar mass of Fe = 56 g/mol

Mass of Fe from the balanced equation = 2 × 56 = 112 g

Molar mass of Fe₂S₃ = (2×56) + (3×32)

= 112 + 96

= 208 g/mol

Mass of Fe₂S₃ from the balanced equation = 1 × 208 = 208 g

SUMMARY:

From the balanced equation above,

112 g of Fe reacted to produce 208 g of Fe₂S₃.

Finally, we shall determine the mass of Fe needed to produce 96 g of Fe₂S₃. This can be obtained as follow:

From the balanced equation above,

112 g of Fe reacted to produce 208 g of Fe₂S₃.

Therefore, Xg of Fe will react to produce 96 g of Fe₂S₃ i.e

Xg of Fe = (112 × 96)/208

Xg of Fe = 51.69 g

Thus, 51.69 g of Fe is needed for the reaction.

8 0
3 years ago
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