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riadik2000 [5.3K]
3 years ago
8

The direction of gas movement is determined by ______________. solubility of the gas in blood size of the gas molecule temperatu

re ph partial pressure differences
Chemistry
1 answer:
pishuonlain [190]3 years ago
4 0
<span>The direction of gas movement is determined by <u>Partial Pressure Difference</u>.

Explanation:
                   According to phenomenon of Diffusion and Effusion gases always move from level of higher concentration to level of lower concentration. In lungs the oxygen moves from external atmosphere to inner body due to difference in partial pressure of Oxygen. Oxygen present in higher quantity outside body moves in through alveoli. And CO</span>₂ present in body moves out through lungs. Same process takes place at tissue level.
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How many atoms are there in 15.0 grams of Sulfur (S)?
aev [14]

Answer:

C

Explanation:

Mol x Avogadro's number

Mol : mass / molar mass

Avogadro's no: 6.02E+23

6 0
2 years ago
If molar mass of M(OH)3 = 78 8. mass of M​
Cerrena [4.2K]

Answer:

From molar mass=total RAM of each individual element

78.8=(16+1)×3+M

78.8-51=M

27.8g/mol=M

5 0
2 years ago
Suppose a 2.95 g of potassium iodide is dissolved in 350. mL of a 62.0 m M aqueous solution of silver nitrate. Calculate the fin
STALIN [3.7K]

Answer : The final molarity of iodide anion in the solution is 0.0508 M.

Explanation :

First we have to calculate the moles of KI and AgNO_3.

\text{Moles of }KI=\frac{\text{Mass of }KI}{\text{Molar mass of }KI}

Molar mass of KI = 166 g/mole

\text{Moles of }KI=\frac{2.95g}{166g/mole}=0.0178mole

and,

\text{Moles of }AgNO_3=\text{Concentration of }AgNO_3\times \text{Volume of solution}=0.0620M\times 0.350L=0.0217mole

Now we have to calculate the limiting and excess reagent.

The given chemical reaction is:

KI+AgNO_3\rightarrow KNO_3+AgI

From the balanced reaction we conclude that

As, 1 mole of KI react with 1 mole of AgNO_3

So, 0.0178 mole of KI react with 0.0178 mole of AgNO_3

From this we conclude that, AgNO_3 is an excess reagent because the given moles are greater than the required moles and KI is a limiting reagent and it limits the formation of product.

Now we have to calculate the moles of AgI

From the reaction, we conclude that

As, 1 mole of KI react to give 1 mole of AgI

So, 0.0178 moles of KI react to give 0.0178 moles of AgI

Thus,

Moles of AgI = Moles of I^- anion = Moles of Ag^+ cation = 0.0178 moles

Now we have to calculate the molarity of iodide anion in the solution.

\text{Concentration of }AgNO_3=\frac{\text{Moles of }AgNO_3}{\text{Volume of solution}}

\text{Concentration of }AgNO_3=\frac{0.0178mol}{0.350L}=0.0508M

Therefore, the final molarity of iodide anion in the solution is 0.0508 M.

3 0
3 years ago
Can anyone draw a diagram of a liebigs condenser
MrMuchimi

I googled it, here it is lol

6 0
2 years ago
In a nuclear power plant control rods are used to
evablogger [386]
Control rods are used<span> in </span>nuclear<span> reactors to </span>control<span> the fission rate of uranium and plutonium. They are composed of chemical elements such as boron, silver, indium and cadmium that are capable of absorbing many neutrons without themselves fissioning.</span>
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3 years ago
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