Answer:
The molecular formula of the compound is C₂H₄F₂ or CH₃CHF₂
Explanation:
From the question given above, the following data were obtained:
Empirical formula of the compound = CH₂F
Fórmula mass of compound = 66 g/mol
Molecular formula of the compound =?
The molecular formula of the compound can be obtained as follow:
Molecular formula = [Empirical formula]ₙ
Molecular formula = [CH₂F]ₙ
[CH₂F]ₙ = 66
[12 + (2×1) + 19] n = 66
[12 + 2+ 19]n = 66
33n = 66
Divide both side by 33
n = 66/33
n = 2
Molecular formula = [CH₂F]ₙ
Molecular formula = [CH₂F]₂
Molecular formula = C₂H₄F₂
Thus, the molecular formula of the compound is C₂H₄F₂ or CH₃CHF₂
Answer:
<em>by radiation</em>
Explanation:
Thermal radiation can occur through matter or through a region of space that is void of matter (i.e., a vacuum). In fact, the heat received on Earth from the sun is the result of electromagnetic waves traveling through the void of space between the Earth and the sun.
<em>hope it helps you answer your question:)</em>
Answer:
Superscript 6 Subscript 2 Baseline Upper H e right arrow Superscript 6 Subscript 3 Baseline Upper L i + Superscript 0 Subscript negative 1 Baseline e
Explanation:
Helium decays by beta emission, in beta emission, the mass number of the parent and daughter nuclei are the same but the atomic number of the daughter nucleus increases by one hence it is found one place to the right of its parent in the periodic table.
Having said this, the decay of Helium to lithium may be written as follows;
6/2He -> 6/3Li + 0/-1e
Answer:
1,42 Å
Explanation:
La longitud de enlace de Bi-I se obtiene por
Bi-I = Radio del átomo de Bi + Radio del átomo de yodo
pero radio del átomo de yodo = 1.39Å
Longitud del enlace Bi-I = 2,81 Å
Por lo tanto, el radio del átomo de Bi = 2,81 Å - 1,39 Å
radio del átomo de Bi = 1,42 Å