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3 years ago

Help me with this problem please? c:

1 answer:

5 0

30*3*60=5400
300*2=600
1500*3=4500
200*10*60=120000

the computer uses more energy.
(you can multiply all results by 60 to get the energy in J, but it's not necessary for the comparison)

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In an experiment Rahul burnt 4 kg fuel and the heat produced was measured to be 160,000 kJ and Raj burnt 2 kg of fuel and heat p

Gnesinka [82]

Answer:

The net calorific value of the fuel 1 is 40000 kilojoules per kilogram.

The net calorific value of the fuel 2 is 50000 kilojoules per kilogram.

Explanation:

The net calorific value is equal to the heat produced ( $Q$ ), in kilojoules, divided by the mass of the burnt fuel ( $m$ ). We proceed to calculate the net calorific value of each fuel:

Fuel 1 ( $m = 4\,kg$ , $Q = 160000\,kJ$ )

$L = \frac{160000\,kJ}{4\,kg}$

$L = 40000\,\frac{kJ}{kg}$

The net calorific value of the fuel 1 is 40000 kilojoules per kilogram.

Fuel 2 ( $m = 2\,kg$ , $Q = 100000\,kJ$ )

$L = \frac{100000\,kJ}{2\,kg}$

$L = 50000\,\frac{kJ}{kg}$

The net calorific value of the fuel 2 is 50000 kilojoules per kilogram.

6 0

3 years ago

Help pls i need this right now

BabaBlast [244]

Answer:

C = - 1.625 i + 6.06 j

Explanation:

Positive angles are measured counterclockwise.

Positive angles are measured counterclockwise. To determine the component on the x axis we use the cosine of the angle while to determine the component on the y axis we use the sine of the angle.

$C_{x}=6.28*cos(105)=-1.625\\C_{y}=6.28*sin(105)=6.06\\$

C = - 1.625 i + 6.06 j

5 0

3 years ago

A box slides down a frictionless ramp.if it starts at rest, what is it’s speed at the bottom?

zhenek [66]

8.854 m/s is the speed of the box after it reaches bottom of the ramp.

Explanation:

From the figure we came to know that height of the block is 4 m.

We know that,

Total "initial energy of an object" = Total "final energy of an object "

Total "initial energy of an object" is = "sum of potential energy" and "kinetic energy" of an object at its initial position.

$\text { "g" acceleration due to gravity is } 9.8 \mathrm{m} / \mathrm{s}^{2}$

$\text { Total initial energy }=\mathrm{m} \times \mathrm{g} \times \mathrm{h}_{\mathrm{i}}+\frac{1}{2} \mathrm{m} v_{i}^{2}$

Initial velocity is “0” as the object does not have starting speed

$\text { Height of the block where the object is placed initially }\left(h_{i}\right) \text { is } 4 \mathrm{m} \text { . }$

$\text { Total initial energy }=\mathrm{m} \times 9.8 \times 4+\frac{1}{2} \mathrm{m} 0^{2}$

Total initial energy = 39.2 × m

$\text { Total final energy }=\mathrm{m} \times \mathrm{g} \times \mathrm{h}_{\mathrm{f}}+\frac{1}{2} m v_{f}^{2}$

$\text { We need to find final velocity } v_f$

$\text { Height of the block where the object is travelled to bottom (h_) is } 0 \mathrm{m} \text { . }$

$\text { Total final energy }=\mathrm{m} \times 9.8 \times 0+\frac{1}{2} m v_{f}^{2}$

Now, Total initial energy of an object = Total final energy of an object

$39.2 \times \mathrm{m}=0.5 \mathrm{m} v_{f}^{2}$

$\frac{39.2}{0.5}=v_{f}^{2}$

$v_{f}^{2}=78.4$

$v_{f}=\sqrt{78.4}$

$v_{f}=8.854 \mathrm{m} / \mathrm{s}$

Final speed is 8.854 m/s.

3 0

3 years ago

Magnetism is a ? A) FORCE B) POWER C) FORM OF ENERGY D) FORM OF ELECTRICITY

Ksivusya [100]

I believe this answer is Force

3 0

3 years ago

Read 2 more answers

Marking branliest!

Ivenika [448]

Answer:

D)evaluating a solution

Explanation:

In this scenario, the next logical step would be evaluating a solution. This is because Jasper and Samantha have already identified the problem/need which is that the robot needs to be able to move a 10-gram weight at least 2 meters and turn in a circle. They also designed and implemented a solution because they have already built the robot. Therefore the only step missing is to evaluate and make sure that the robot they built is able to complete the requirements.

7 0

3 years ago