A particle has centripetal acceleration whenever it's a making a turn of radius R. If the particle is moving at a constant tangential speed v throughout the turn, then the magnitude of centripetal acceleration is
v²/R
If the particle is following a uniformly circular path, then it moves in a circle of radius R and travels a distance equal to its circumference, 2πR. Let T be the time it takes to complete one such loop. Then the entire circle is traversed with speed v = 2πR/T, so that the centripetal acceleration is also given by
v²/R = (2πR/T)²/R = 4π²R/T²
<em>im confused hold on imma send you a link to the answer</em>Explanation:
Hello,
Here is your answer:
The proper answer to this question is option D "<span>centrifugal".</span>
The force centrifugal is the force that holds the moon with the Earth and the centrifugal force is two times stronger with the Earth and the sun.
Your answer is D.
If you need anymore help feel free to ask me!'
Hope this helps!
<span>
the horizontal velocity would be equal to
Vh = sin (40) /60
= 0.74 * 60
= 44
</span>
the Vertical velocity would be equal to
<span>Vv = cos(40) * 60
=40</span>
The answer is the suns gravity
