Initial velocity = Vo= 25 m/s
Final velocity = V = x
Acceleration= a = 6 m/s^2
time= t = 4 seconds
Appy the equation:
V = Vo + at
Replacing:
V = 25 + 6(4) = 25 + 24 = 49 m/s
Answer:
a) k = 2231.40 N/m
b) v = 0.491 m/s
Explanation:
Let k be the spring force constant , x be the compression displacement of the spring and v be the speed of the box.
when the box encounters the spring, all the energy of the box is kinetic energy:
the energy relationship between the box and the spring is given by:
1/2(m)×(v^2) = 1/2(k)×(x^2)
(m)×(v^2) = (k)×(x^2)
a) (m)×(v^2) = (k)×(x^2)
k = [(m)×(v^2)]/(x^2)
k = [(3)×((1.8)^2)]/((6.6×10^-2)^2)
k = 2231.40 N/m
Therefore, the force spring constant is 2231.40 N/m
b) (m)×(v^2) = (k)×(x^2)
v^2 = [(k)(x^2)]/m
v = \sqrt{ [(k)(x^2)]/m}
v = \sqrt{ [(2231.40)((1.8×10^-2)^2)]/(3)}
= 0.491 m/s
Option B is correct. If an incident light ray hits a flat, smooth object at 28°. It will reflect off at an angle of 28°.
<h3>What is the law of reflection?</h3>
The law of reflection specifies that upon reflection from a downy surface, the slope of the reflected ray is similar to the slope of the incident ray.
The reflected ray is consistently in the plane determined by the incident ray and perpendicular to the surface at the point of reference of the incident ray.
When the light rays descend on the smooth surface, the angle of reflection is similar to the angle of incidence, also the incident ray, the reflected ray, and the normal to the surface all lie in a similar plane.
If an incident light ray hits a flat, smooth object at 28 degrees, it will reflect off at an angle of 28°.
Hence, option B is correct
To learn more about the law of reflection, refer to the link;
brainly.com/question/12029226
#SPJ1
Answer:
The basic construction, unchanged since Torricelli's experiment in 1643, is a glass tube about three feet long, closed at one end, filled with mercury, and inverted with the open end immersed in a cistern of mercury.
Answer:
The final speed of the train and Bambi after collision is 7.44 m/s
Explanation:
Given;
mass of the train, m₁ = 1000kg
mass of Bambi, m₂ = 75kg
initial speed of the train, u₁ = 8 m/s
initial speed of Bambi, u₂ = 0 m/s
If Bambi gets stuck to the front of the train, then the collision is inelastic.
m₁u₁ + m₂u₂ = v(m₁ + m₂)
where;
v is the final speed of the train and Bambi after collision
Substitute the given values and solve for v
1000 x 8 + 75 x 0 = v (1000 + 75)
8000 = v (1075)
v = 8000/1075
v = 7.44 m/s
Therefore, the final speed of the train and Bambi after collision is 7.44 m/s
