1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
AnnyKZ [126]
4 years ago
12

The gravitational force of a star on an orbiting planet 1 is f1. planet 2, which is four times as massive as planet 1 and orbits

at three times larger distance from the star, experiences gravitational force f2
Physics
1 answer:
Keith_Richards [23]4 years ago
8 0
<span>Answer: F=GMm/r^2 where G is the newtonian grav cst, M the mass of the star, m the mass of the planet, and r the planet-star distance F1=GMm1/r1^2 F2=GMm2/r^2 F2/F1 = [GMm2/r2^2]/[GMm1/r1^2] F2/F1=(m2/m1)(r1/r2)^2 = (2)(1/2)^2 = 1/2 because m2/m1=2 and r2/r1=2</span>
You might be interested in
Any clue on this one
rodikova [14]

Answer: First option

Explanation: The higher the frequency, the higher the energy.

λν=c where λ is the wavelength, ν is the frequency and c is the speed of light. So when wavelength decreases, v increases and so does energy.

An AM radio wave has a very long wavelength. It therefore has a very low frequency and low energy.

A light wave has a very short wavelength. It therefore has a high frequency and high energy.

3 0
3 years ago
If Jupiter were 10 times more massive, it would generate nuclear fusion in its core and be a star instead of a planet. If Jupite
OverLord2011 [107]

Answer:

False

Explanation:

Let me put it in numbers. Jupiter has mass of 1.898x10^27Kg, make it 10 times as much and it becomes 1.898x10^28 Kg.

TRAPPIST-1, smallest star ever found has Mass of 1.77x10^29Kg, that is around 93 times larger than the mass of Jupiter.

Clearly 10 times as much is not enough to generate fusion reaction and become a star, in theory Jupiter must be at least 85 times larger than it's current mass to be able to generate fusion reaction and become a star.

So i think we can conclude that if Jupiter were to have 10 times of its own mass, it would not become a star, therefore the given statement is False.

5 0
3 years ago
Read 2 more answers
A wheel has a constant angular acceleration of 1.9 rad/s2. During a certain 7.0 s interval, it turns through an angle of 63 rad.
Anarel [89]

Answer:

4.5s

Explanation:

That must be the right answer.

3 0
3 years ago
Car a has a mass of 5 kg and 10 m/s .cart B has a mass of 10 kg and 5 m/s .which of the following statements best compares the i
weeeeeb [17]

The two cars have same momentum

Explanation:

The momentum of an object is given by the equation

p=mv

where

m is the mass of the object

v is its velocity

For the car A in this problem,

m = 5 kg

v = 10 m/s

So its momentum is

p_A = (5 kg)(10 m/s) = 50 kg m/s

For car B we have,

m = 10 kg

v = 5 m/s

So its momentum is

p_B = (10 kg)(5 m/s)=50 kg m/s

Therefore, the two cars have same momentum.

Learn more about momentum:

brainly.com/question/7973509

brainly.com/question/6573742

brainly.com/question/2370982

brainly.com/question/9484203

#LearnwithBrainly

7 0
3 years ago
Air enters a nozzle steadily at 2.21 kg/m3 and 20 m/s and leaves at 0.762 kg/m3 and 150 m/s. If the inlet area of the nozzle is
saveliy_v [14]

Answer:

a) The mass flow rate through the nozzle is 0.27 kg/s.

b) The exit area of the nozzle is 23.6 cm².

Explanation:

a) The mass flow rate through the nozzle can be calculated with the following equation:

\dot{m_{i}} = \rho_{i} v_{i}A_{i}

Where:

v_{i}: is the initial velocity = 20 m/s

A_{i}: is the inlet area of the nozzle = 60 cm²  

\rho_{i}: is the density of entrance = 2.21 kg/m³

\dot{m} = \rho_{i} v_{i}A_{i} = 2.21 \frac{kg}{m^{3}}*20 \frac{m}{s}*60 cm^{2}*\frac{1 m^{2}}{(100 cm)^{2}} = 0.27 kg/s  

Hence, the mass flow rate through the nozzle is 0.27 kg/s.

b) The exit area of the nozzle can be found with the Continuity equation:

\rho_{i} v_{i}A_{i} = \rho_{f} v_{f}A_{f}

0.27 kg/s = 0.762 kg/m^{3}*150 m/s*A_{f}

A_{f} = \frac{0.27 kg/s}{0.762 kg/m^{3}*150 m/s} = 0.00236 m^{2}*\frac{(100 cm)^{2}}{1 m^{2}} = 23.6 cm^{2}

Therefore, the exit area of the nozzle is 23.6 cm².

I hope it helps you!                                                                  

5 0
3 years ago
Read 2 more answers
Other questions:
  • A radioactive nucleus has a half-life of 5 x 108 years. Assuming that a sample of rock (say, in an asteroid) solidified right af
    5·1 answer
  • The electrostatic force that describes why charged objects attract to one another is also called ________________.
    11·1 answer
  • What process generters a current by moving an electrical conductor though a magnetic field
    9·1 answer
  • WILL AWARD BRAINLLIEST!!!!
    8·2 answers
  • The energy supplied to a speaker is increased. What will happen to the sound the speaker produces? A) The sound will be lower pi
    10·2 answers
  • in the absences of friction, gravity, and all other external forces, what kind of speed will an object display if it’s travel fr
    14·1 answer
  • A Canadian college student who has taken an astronomy class goes home for the holidays and persuades his parents to let him borr
    6·1 answer
  • How did photosynthesis start?
    13·2 answers
  • What is the change in the internal energy of a system that does 600 joules of work and absorbs 800 joules of heat?
    11·2 answers
  • Which image shows a nonrenewable resource?<br><br> sun<br> fire<br> can<br> plant
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!