A 105 kg crate initially at rest on a horizontal floor requires a 705 N horizontal force
1 answer:
Answer:
μs = 0.68
μk = 0.577
Explanation:
In order to solve this problem, we must remember that the normal force on a body that rests on a horizontal surface is equal to the weight of a body but in the opposite direction.
The friction force is defined as the product of the coefficient of friction by the normal force.
Now when the body is in motion we have that the coefficient of friction is the dynamic one.
595 = μk*N
μk = 595/1030.05
μk = 0.577
Now to start moving it requires a force of 705 [N].
705 = μs*N
μs = 705/1030.05
μs = 0.68
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