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Wewaii [24]
2 years ago
14

A 105 kg crate initially at rest on a horizontal floor requires a 705 N horizontal force

Physics
1 answer:
DENIUS [597]2 years ago
3 0

Answer:

μs = 0.68

μk = 0.577

Explanation:

In order to solve this problem, we must remember that the normal force on a body that rests on a horizontal surface is equal to the weight of a body but in the opposite direction.

W=N\\N=m*g\\N=105*9.81\\N=1030.05[N]

The friction force is defined as the product of the coefficient of friction by the normal force.

Now when the body is in motion we have that the coefficient of friction is the dynamic one.

595 = μk*N

μk = 595/1030.05

μk = 0.577

Now to start moving it requires a force of 705 [N].

705 = μs*N

μs = 705/1030.05

μs = 0.68

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Please do number 25! Explain how you got your answer with detail to get Brainliest! Thank you!
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John weighs 200 pounds.
In order to lift himself up to a higher place, he has to exert force of 200 lbs.

The stairs to the balcony are 20-ft high.
In order to lift himself to the balcony, John has to do
(20 ft) x (200 pounds)  =  4,000 foot-pounds of work.

If he does it in 6.2 seconds, his RATE of doing work is
(4,000 foot-pounds) / (6.2 seconds)  =  645.2 foot-pounds per second.

The rate of doing work is called "power".

(If we were working in the metric system (with SI units),
the force would be in "newtons", the distance would be in "meters",
1 newton-meter of work would be 1 "joule" of work, and
1 joule of work per second would be 1 "watt".
Too bad we're not working with metric units.)

So back to our problem.

John has to do 4,000 foot-pounds of work to lift himself up to the balcony,
and he's able to do it at the rate of 645.2 foot-pounds per second.

Well, 550 foot-pounds per second is called 1 "horsepower".

So as John runs up the steps to the balcony, he's doing the work
at the rate of

           (645.2 foot-pounds/second) / (550 ft-lbs/sec per HP)

=  1.173 Horsepower.  GO JOHN !

(I'll betcha he needs a shower after he does THAT 3 times.)
_______________________________________________

Oh my gosh !  Look at #26 !  There are the metric units I was talking about.

Do you need #26 ?

I'll give you the answers, but I won't go through the explanation,
because I'm doing all this for only 5 points.

a).  5
b).  750 Joules
c).  800 Joules
d).  93.75%

You're welcome.

And #27 is 0.667 m/s .
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3 years ago
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210 Pb ---> -ie + 210 B:
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3 years ago
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alukav5142 [94]

Answer:

25000 V

Explanation:

The formula for potential is

V = Kq/r

Potential at B due to the charge placed at origin O

V1 = K q / OB

V_{1}= \frac{9 \times 10^{9} \times 30 \times 10^{-6}}{27}

V1 = 10000 V

Potential at B due to the charge placed at A

V2 = K q / AB

V_{2}= \frac{9 \times 10^{9} \times 30 \times 10^{-6}}{18}

V2 = 15000 V

Total potential at B

V = V1 + V2 = 10000 + 15000 = 25000 V

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Answer:

0.12m/s

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frequency 'f' is unknown but we can get frequency from f = 1/T = 1/1 = 1Hz

therefore, v= 0.12 × 1 = 0.12m/s

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