A 105 kg crate initially at rest on a horizontal floor requires a 705 N horizontal force
1 answer:
Answer:
μs = 0.68
μk = 0.577
Explanation:
In order to solve this problem, we must remember that the normal force on a body that rests on a horizontal surface is equal to the weight of a body but in the opposite direction.
The friction force is defined as the product of the coefficient of friction by the normal force.
Now when the body is in motion we have that the coefficient of friction is the dynamic one.
595 = μk*N
μk = 595/1030.05
μk = 0.577
Now to start moving it requires a force of 705 [N].
705 = μs*N
μs = 705/1030.05
μs = 0.68
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Answer:
a)
b)
c)
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the gravitational potential energy is given by:
The kinetic energy is given by:
the initial kinetic energy is zero because the motion started from rest, so:
applying the conservation of energy theorem:
The work done by the friction force is given by:
the angle of the force is 180 degrees because it's against the movement:
Answer:
The specific question is not stated, however the general idea is given in the attached picture. The electric field in each region can be found by Gauss’ Law.
at r < R:
Since the solid sphere is conducting, the total charge Q is distributed over the surface, and the electric field inside the sphere is zero.
E = 0.
at R < r < 2R:
The electric field can be found by Gauss’ Law as in the attachment. The green pencil shows this exact region.
at 2R < r:
The electric field can again be found by Gauss’ Law, the blue pencil shows the calculations for this region.
Explanation:
Gauss’ Law is straightforward when applied to spheres. The area of the sphere is , and the enclosed charge is given in the question as Q for the inner sphere, and 2Q for the whole system.
