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3 years ago

What is groundwater flow

Chemistry

2 answers:

vovikov84 [41]3 years ago

7 0

Groundwater is water that is found underground in cracks and spaces in the soil ,sand and rocks

Sliva [168]3 years ago

4 0

Part of the steam flow that has infiltrated the ground, has entered the phreatic zone and has been discharged into a stream channel.

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Given that the density of gold and sand are 19. 3 g/cm^3 and 2. 95 g/cm^3, respectively, and that the density of the mixture is

SOVA2 [1]

The percent by mass of gold in the mixture will be 34.5%.

How to calculate the percentage?

The following information can be deduced based on the information given:

Density of gold = 19.3 g/cm³.

Density of sand = 2.94 g/cm³

Density of mixture = 4.17 g/cm³

It should be noted that when we find the volume fo gold on a 1cm³ sample, then we can be able to find that mass. The volume of gold will be calculated thus:

4.17 = [(19.3x + 2.95(1 - x)]

4.17 = 19.3x + 2.95 - 2.95x

4.17 = 16.35x + 2.95

x = 0.0746cm³

The mass of gold will be:

= 0.0746 × 19.3

= 1.44

The percent by mass of gold in the mixture will be:

= 1.44/4.17 × 100

= 34.5%

In conclusion, the percent by mass of gold in the mixture will be 34.5%.

What is Mass?

Mass is a physical body's total amount of matter. It also serves as a gauge for the body's inertia, or resistance to acceleration (change in velocity) in the presence of a net force. The strength of an object's gravitational pull to other bodies is also influenced by its mass.

The kilogram is the primary mass unit in the SI (kg). Even though weight is frequently measured using a spring scale rather than a balancing scale and directly compared with known masses, mass is not the same as weight in physics. Due to the lower gravity on the Moon, an object would weigh less than it does on Earth while maintaining the same mass. Given that weight is a force.

To learn more about mass equation visit here:

brainly.com/question/19600926?referrer=searchResults

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3 0

2 years ago

What should i buy from target.i was given 100 dollars. serious answers only!

denis23 [38]

Answer:

save it for future references

Explanation:

3 0

3 years ago

Read 2 more answers

What is the experimental group? on edpuzzle

RideAnS [48]

An experimental group, also known as a treatment group, receives the treatment whose effect researchers wish to study, whereas a control group does not. They should be identical in all other ways

3 0

3 years ago

Read 2 more answers

How many moles of MgS2O3 are in 247 g of the compound?

lara [203]

Moles of MgS2O3 = 247/136 = 1.81 moles. Molecular mass of MgS2O3 = 136

6 0

3 years ago

If 150 g dimethylhydrazine reacts with excess dinitrogen tetroxide and the product gases are collected at 127oC in an evacuated

zhuklara [117]

Answer : The the partial pressure of the nitrogen gas is 0.981 atm.

The total pressure in the tank is 2.94 atm.

Explanation :

The balanced chemical reaction will be:

$(CH_3)_2N_2H_2(l)+2N_4O_4(l)\rightarrow 3N_2(g)+4H_2O(g)+2CO_2(g)$

First we have to calculate the moles of dimethylhydrazine.

Mass of dimethylhydrazine = 150 g

Molar mass of dimethylhydrazine =60.104 g/mole

$\text{Moles of dimethylhydrazine}=\frac{\text{Mass of dimethylhydrazine}}{\text{Molar mass of dimethylhydrazine}}$

$\text{Moles of dimethylhydrazine}=\frac{150g}{60.104g/mole}=2.49mole$

Now we have to calculate the moles of $N_2$ gas.

From the balanced chemical reaction we conclude that,

As, 1 mole of $(CH_3)_2N_2H_2$ react to give 3 moles of $N_2$ gas

So, 2.49 mole of $(CH_3)_2N_2H_2$ react to give $2.49\times 3=7.47$ moles of $N_2$ gas

Now we have to calculate the partial pressure of nitrogen gas.

Using ideal gas equation :

$PV=nRT\\\\P_{N_2}=\frac{nRT}{V}$

where,

P = Pressure of $N_2$ gas = ?

V = Volume of $N_2$ gas = 250 L

n = number of moles $N_2$ gas = 7.47 mole

R = Gas constant = $0.0821L.atm/mol.K$

T = Temperature of $N_2$ gas = $127^oC=273+127=400K$

Putting values in above equation, we get:

$P_{N_2}=\frac{(7.47mole)\times (0.0821L.atm/mol.K)\times 400K}{250L}=0.981atm$

Thus, the partial pressure of the nitrogen gas is 0.981 atm.

Now we have to calculate the total pressure in the tank.

Formula used :

$P_{N_2}=X_{N_2}\times P_T$

$P_T=\frac{1}{X_{N_2}}\times P_{N_2}$

$P_T=\frac{1}{(\frac{n_{N_2}}{n_T})}\times P_{N_2}$

$P_T=\frac{n_{T}}{n_{N_2}}\times P_{N_2}$

where,

$P_T$ = total pressure = ?

$P_{N_2}$ = partial pressure of nitrogen gas = 0.981 atm

$n_{N_2}$ = moles of nitrogen gas = 3 mole (from the reaction)

$n_{T}$ = total moles of gas = (3+4+2) = 9 mole (from the reaction)

Now put all the given values in the above formula, we get:

$P_T=\frac{9mole}{3mole}\times 0.981atm=2.94atm$

Thus, the total pressure in the tank is 2.94 atm.

8 0

3 years ago