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zavuch27 [327]
3 years ago
14

Is yeast living or non living?

Chemistry
2 answers:
enyata [817]3 years ago
8 0
Yeast is a living organism
grandymaker [24]3 years ago
6 0

Answer:

Yeast is living.

Explanation:

Yeast is a type of fungus used in making bread. Fungus is a group of living organisms.

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What will the formula of a diatomic element look like?
egoroff_w [7]

Answer:

or example, most samples of the elements hydrogen, oxygen, and nitrogen are composed of molecules that contain two atoms each (called diatomic molecules) and thus have the molecular formulas H2, O2, and N2, respectively. ... A molecule of sulfur is composed of eight sulfur atoms and is therefore written as S8.

6 0
3 years ago
The melting point of sugar is 186°C. At room temperature, in which state is sugar found
Viktor [21]

Answer:

solid

Explanation:Sucrose is a solid at STP, which stands for standard temperature and pressure.

8 0
3 years ago
You have 0.21 moles of Al how many atoms do you have
ZanzabumX [31]

Number of atoms : 1.26 x 10²³

<h3>Further explanation  </h3>

The mole is the number of particles(molecules, atoms, ions) contained in a substance  

1 mol = 6.02.10²³ particles

Can be formulated

N=n x No

N = number of particles

n = mol

No = Avogadro's = 6.02.10²³

0.21 moles of Al, so n = 0.21

Number of atoms :

\tt N=0.21\times 6.02\times 10^{23}\\\\N=1.26\times 10^{23}

8 0
3 years ago
If 55.8 ml of bacl2 solution is needed to precipitate all the sulfate ion in a 742 mg sample of na2so4, what is the molarity of
lukranit [14]

Answer is: the molarity of the solution is 0.0936 M.

Balanced chemical reaction: BaCl₂(aq) + Na₂SO₄(aq) → BaSO₄(s) + 2NaCl(aq).

Net ionic reaction: Ba²⁺ + SO₄²⁻ → BaSO₄(s).

V(BaCl₂) = 55.8 mL; volume of barium chloride solution.

V(BaCl₂) = 55.8 mL ÷ 1000 mL/L = 0.0558 L.

m(Na₂SO₄) = 742 mg ÷ 1000 mg/g.

m(Na₂SO₄) = 0.742 g; mass of sodium sulfate.

n(Na₂SO₄) = m(Na₂SO₄) ÷ M(Na₂SO₄).

n(Na₂SO₄) = 0.742 g ÷ 142.04 g/mol.

n(Na₂SO₄) = 0.00522 mol; amount of substance.

From chemical reaction: n(Na₂SO₄) : n(BaCl₂) = 1 : 1.

n(BaCl₂) = 0.00522 mol.

c(BaCl₂) = n(BaCl₂) ÷ V(BaCl₂).

c(BaCl₂) = 0.00522 mol ÷ 0.0558 L.

c(BaCl₂) = 0.0936 M.

3 0
3 years ago
During the experiment is when data is
Nat2105 [25]
The answer is A. You record ,write down, what is happening with the experiment.
8 0
3 years ago
Read 2 more answers
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