Desert plants work hard to make use of what's available. They use the sun's energy to convert carbon dioxide (CO2) and water (H2O) into sugar, a process called photosynthesis. During this process, stomata on a plant's leaves and stems open to absorb carbon dioxide from the air and in return release oxygen. :)
Answer:
63.616
Explanation:
DATA
1. first atomic mass;m1=63
- second atomic mass;m2=65
- first percentage;p1= 69.2%
- second percentage me;p2=30.8%
- average mass;avg= ?
SOLUTION
avg=<u> (m1)(p1) + (m2)(</u><u>p2</u><u>)</u>
100
avg= <u>(63)(69.2) + (65)(30.8)</u>
100
avg= <u>4</u><u>3</u><u>5</u><u>9</u><u>.</u><u>6</u><u> </u><u>+</u><u> </u><u>2</u><u>0</u><u>0</u><u>2</u>
100
avg= <u>6361.6</u>
100
avg= 63.616
If the stigma is messed up it is hard for bees or insects to pollinate because the way they pollinate is by eating the nectar from the stigma and stick the pollen on their body and stick it on the stigma.
But if there is no stigma=no pollination
A good example of a model is a lily
Atomic mass is the total mass of neutrons and protons in a certain isotope. It is usually called: AMU or atomic mass unit.
Answer:
pH = 5.54
Explanation:
The pH of a buffer solution is given by the <em>Henderson-Hasselbach (H-H) equation</em>:
- pH = pKa + log
![\frac{[CH_3COO^-]}{[CH_3COOH]}](https://tex.z-dn.net/?f=%5Cfrac%7B%5BCH_3COO%5E-%5D%7D%7B%5BCH_3COOH%5D%7D)
For acetic acid, pKa = 4.75.
We <u>calculate the original number of moles for acetic acid and acetate</u>, using the <em>given concentrations and volume</em>:
- CH₃COO⁻ ⇒ 0.377 M * 0.250 L = 0.0942 mol CH₃COO⁻
- CH₃COOH ⇒ 0.345 M * 0.250 L = 0.0862 mol CH₃COOH
The number of CH₃COO⁻ moles will increase with the added moles of KOH while the number of CH₃COOH moles will decrease by the same amount.
Now we use the H-H equation to <u>calculate the new pH</u>, by using the <em>new concentrations</em>:
- pH = 4.75 + log
= 5.54