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IgorLugansk [536]
3 years ago
13

Which force causes a wagon to speed up as it rolls down a hill?

Physics
2 answers:
Temka [501]3 years ago
7 0
Gravity is the only one helping it.
Delicious77 [7]3 years ago
6 0

Answer: The correct answer is force of gravity.

Explanation:

Gravity is the force with which one body attracts the other body.

It goes down a hill with the increase in the kinetic energy. The kinetic energy is due to the motion of a wagon.

At the hill the gravity is lesser in comparison to the gravity on the surface of the earth.

When a wagon rolls down a hill it speeds up. Here, the earth attracts the wagon with the force of gravity. It accelerates down a hill with an acceleration due to gravity.

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A force of F = (2.00ˆi + 3.00ˆj) N is applied to an object that is pivoted about a fixed axle aligned along the z coordinate axi
Vladimir [108]

Explanation:

It is given that,

Force applied to object, F=(2i+3j)\ N

Position, r=(4i+5j)\ m  

(b) The cross product of force and position vector is used to find the net torque about the z axis. It is given by :

\tau=F\times r

\tau=(2i+3j) \times (4i+5j)

\tau=\begin{pmatrix}0&0&-2\end{pmatrix}

or

\tau=(-2k)\ N-m

The torque is acting in -z axis.

(a) The magnitude of torque is given by :

|\tau|=\sqrt{(-2)^2}

|\tau|=2\ N-m

Hence, this is the required solution.

5 0
3 years ago
Find the slope of the line that passes through the points (-1, 3) and (2, -5)-
spayn [35]

Answer:

m=−8/3

Explanation:

6 0
3 years ago
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A 0.50-kg block slides across a tabletop with an initial velocity of 20 cm/s and comes to rest in a distance of 70 cm. Find the
mars1129 [50]

Answer:

FAE= 0.014 N

Explanation:

The KE of block is decreased because of the slowing action of the friction force .

Change in KE of block = work done on block by friction ƒ

⠀ ➪ ½mu²ƒ - ½mu²i = Fƒs cos θ

Because the friction force on the block is opposite in direction to the displacement , cos θ = -1

➢ Using Uƒ = 0 , Vƒ = 0.20 m/s , and s = 0.70 m

✒ We find ,

➪½mu²ƒ - ½mu²i = Fƒs cos θ

➪0-½ (0.50 kg) (0.20 m/s)² = (Fƒ) (0.70 m) (-1)

➪ Fƒ = 0.014 N

Hope this helped, can i pls have brainliest

6 0
3 years ago
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An 67-kg jogger is heading due east at a speed of 2.3 m/s. A 70-kg jogger is heading 61 ° north of east at a speed of 1.3 m/s. F
ololo11 [35]

Answer

given,

mass of jogger  = 67 kg

speed in east direction = 2.3 m/s

mass of jogger 2 = 70 Kg

speed  = 1.3 m/s  in  61 ° north of east.

jogger one

P_1 = m_1 v_1 \hat{i}

P_1 = 67 \times 2.3\hat{i}

P_1 = 154.1 \hat{i}

P_2 = m_2 v_2 \hat{i} +m_2 v_2 \hat{j}

P_2 = 70\times v cos \theta \hat{i} +70\times v sin \theta \hat{j}

P_2 = 70\times 1.3 cos 61^0 \hat{i} +70\times 1.3 sin 61^0\hat{j}

P_2 = 44.12\hat{i} +79.59\hat{j}

now

P = P₁ + P₂

P = 198.22 \hat{i} +79.59 \hat{j}

magnitude

P = \sqrt{198.22^2 + 79.59^2}

P =213.60 kg.m/s

\theta = tan^{-1}\dfrac{79.59}{198.22}

\theta = 21.87

the angle is \theta = 21.87 north of east

7 0
3 years ago
Which type of energy is stored in chemical compounds and released in chemical reactions?
astraxan [27]

Answer:

potential

Explanation:

4 0
3 years ago
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