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2 years ago

Which force causes a wagon to speed up as it rolls down a hill?

Physics

2 answers:

Temka [501]2 years ago

7 0

Gravity is the only one helping it.

Delicious77 [7]2 years ago

6 0

Answer: The correct answer is force of gravity.

Explanation:

Gravity is the force with which one body attracts the other body.

It goes down a hill with the increase in the kinetic energy. The kinetic energy is due to the motion of a wagon.

At the hill the gravity is lesser in comparison to the gravity on the surface of the earth.

When a wagon rolls down a hill it speeds up. Here, the earth attracts the wagon with the force of gravity. It accelerates down a hill with an acceleration due to gravity.

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The direction of the acceleration of an object on a(n) _______________________ path is toward the _______________________ of the

aleksandrvk [35]

Answer:

circular...center

Explanation:

Physics

8 0

3 years ago

A parallel plate capacitor stores charge, and thus, stores energy in the form of electric potential energy. The total energy sto

DIA [1.3K]

Answer:

The charges on the plates,

Explanation:

A capacitor is an electronic device that can be used for storing of charges. A parallel plate capacitor consists of two plates of equal area separated by a dielectric constant. The energy stored in the capacitor is in the form of potential energy which comes into play during the discharging process of the capacitor.

The energy stored depends majorly on the voltage, area of the plates, distance between the plates and the nature of the dielectric constant of the material between the plates. But it does not depend on the charges on the plates.

7 0

3 years ago

lanet R47A is a spherical planet where the gravitational acceleration on the surface is 3.45 m/s2. A satellite orbitsPlanet R47A

qaws [65]

$2.6×10^6\:\text{m}$

Explanation:

The acceleration due to gravity g is defined as

$g = G\dfrac{M}{R^2}$

and solving for R, we find that

$R = \sqrt{\dfrac{GM}{g}}\:\:\:\:\:\:\:(1)$

We need the mass M of the planet first and we can do that by noting that the centripetal acceleration $F_c$ experienced by the satellite is equal to the gravitational force $F_G$ or

$F_c = F_G \Rightarrow m\dfrac{v^2}{r} = G\dfrac{mM}{r^2}\:\:\:\:\:(2)$

The orbital velocity v is the velocity of the satellite around the planet defined as

$v = \dfrac{2\pi r}{T}$

where r is the radius of the satellite's orbit in meters and T is the period or the time it takes for the satellite to circle the planet in seconds. We can then rewrite Eqn(2) as

$\dfrac{4\pi^2 r}{T^2} = G\dfrac{M}{r^2}$

Solving for M, we get

$M = \dfrac{4\pi^2 r^3}{GT^2}$

Putting this expression back into Eqn(1), we get

$R = \sqrt{\dfrac{G}{g}\left(\dfrac{4\pi^2 r^3}{GT^2}\right)}$

$\:\:\:\:=\dfrac{2\pi}{T}\sqrt{\dfrac{r^3}{g}}$

$\:\:\:\:=\dfrac{2\pi}{(1.44×10^4\:\text{s})}\sqrt{\dfrac{(5×10^6\:\text{m})^3}{(3.45\:\text{m/s}^2)}}$

$\:\:\:\:= 2.6×10^6\:\text{m}$

5 0

2 years ago

A gas sample is confined within a chamber that has a movable piston. A small load is placed on the piston; and the system is all

timurjin [86]

Explanation:

It is given that,

Total weight of the piston, W = F = 70 N

Area of the piston, $a=5\times 10^{-4}\ m^2$

Let P is the pressure exerted on the piston by the gas. The force per unit area is called the pressure exerted pressure of the gas. Mathematically, it is given by :

$P=\dfrac{F}{A}$

$P=\dfrac{70\ N}{5\times 10^{-4}\ m^2}$

$P=1.4\times 10^5\ Pa$

We know that the atmospheric pressure is given by :

$P_o=1.013\times 10^5\ Pa$

So, the pressure is given by :

$p=P+P_o$

$p=1.4\times 10^5+1.013\times 10^5$

$p=2.41\times 10^5\ Pa$

Hence, this is the required solution.

7 0

3 years ago

Technician A says that side post terminals need to be removed to inspect them for corrosion. Technician B says that side post te

zlopas [31]

Answer: C

Explanation: Side post terminals need to be removed to inspect them for corrosion.

Over tightening the terminal bolt can damage side post terminals.

The battery terminals and cable ends can corrode especially when the battery or car is not used for a long period of time. Corrosion limits a battery's lifespan and so should be prevented. To inspect the areas where corrosion occur on a side-post battery, you need to remove the terminals.

Also, it is true that over tightening the terminal bolt can damage the side post terminals. The covering on the battery can become twisted, and make the seals on the terminals leak.

4 0

3 years ago