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astraxan [27]
3 years ago
8

The velocity versus time graph of particle A is tangent to the velocity versus time graph for particle B at point O. What is the

acceleration of the particle A at point O?
A. -0.85 meters/second2
B. 1.16 meters/second2
C. -1.16 meters/second2
D. -0.9 meters/second2

Physics
1 answer:
Fudgin [204]3 years ago
3 0

Answer: C. -1.16 meters/second2

Explanation:

A= v/t (velocity/time)

in this case: v=7 and t=6

So, A= 7/6

A=1.16

The graph is decreasing so accelleration would be negative

A= <u>-1.16 meters/second2</u>

<u>Option C!</u> ; )

<u></u>

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3 years ago
How many coulombs of positive charge are there in 47.0 gm of plutonium, given its atomic mass is 244 and that each plutonium ato
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Using the atomic mass of pluonium atoms (244 g/mol), you can calculate the number of atoms in 47.0 g. Then, knowing that each plutonium atom has 96 protons, you calculate the number of protons in the 47.0 g sample. Finally, using the positive charge of one proton, you calculate the total positive charge in the 47.0 g of plutonium.

<u>1. Number of atoms of plutonium in 47.0 g</u>

  • Number of moles = mass / atomic mass = 47.0 g / 244 = 0.1926 moles

  • Number of atoms = number of moles × 6.022 × 10²³ atoms/mol

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<u>3. Charge</u>

<u />

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  • Charge = 1.602×10⁻¹⁹ C/proton × 1.11385×10²⁵ protons = 1.78×10⁶C
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