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const2013 [10]
3 years ago
13

A 523.2-W space heater is designed for operation in Germany, where household electrical outlets supply 230 V (rms) service. What

is the power output of the heater when plugged into a 120-V (rms) electrical outlet in a house in the United States
Physics
1 answer:
photoshop1234 [79]3 years ago
6 0

Answer:

power = 142.4 W

Explanation:

power of heater in Germany (P₁) = 523.2 W

power of heater in America (P₂) = ?

outlet voltage in Germany (V₁) = 230 V

outlet voltage in America (V₂) = 120 V

  • While in Germany, power = \frac{V₁^{2}}{R}

         523.2 = \frac{230^{2}}{R}

         R = 101.1

  • While in America, also power = \frac{V₂^{2}}{R}

         using the value of R gotten above

         power = \frac{120^{2}}{101.1}

        power = 142.4 W

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Brilliant_brown [7]

Answer:

Work done, W=(0.378i-1.092j)\ J

Explanation:

Displacement,

d=(3i-6.5j)\ mm\\\\d=(0.003i-0.0065j)\ m

Force, F=(126i+168j)\ N

Work done by the opponent do on the football player is given by :

W=F{\cdot} d\\\\W=(126i+168j){\cdot} (0.003i-0.0065j)\ m\\\\W=(0.378i-1.092j)\ J

So, the work done by the opponent do on the football player is  (0.378i-1.092j)\ J.

4 0
3 years ago
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iren [92.7K]

Answer:

h = 11.25m

Explanation:

mgh = 1/2mv2

gh = 1/2v2

10 x h = 1/2 x 15 x 15

20 x h = 225

h = 225/20

h = 11.25m

3 0
4 years ago
A 1.2 nf parallel-plate capacitor has an air gap between its plates. Its capacitance increases by 3.0 nf when the gap is filled
Damm [24]

Answer:

2.5

Explanation:

The capacitance of a parallel-plate capacitor filled with dielectric is given by

C=kC_0

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In this problem,

C_0=1.2 nF is the capacitance of the capacitor in air

C=3.0 nF is the capacitance with the dielectric inserted

Solving the equation for k, we find

k=\frac{C}{C_0}=\frac{3.0 nF}{1.2 nF}=2.5

3 0
3 years ago
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PERIOD OF THE LEG The period of the leg can be approximated by treating the leg as a physical pendulum, with a period of Equatio
Lesechka [4]

Answer:

Explanation:

We can see from the question that

        T 2\pi\sqrt{\frac{I}{mgh} }

  and  I = \frac{ml^2}{3}

           m = 16% of  67kg

 =>      m =10kg

      from the question  l =48% of 1.83m

 Substituting this into the equation

                 I = \frac{10.72 * (0.8784)^2}{3}

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From the equation above

      T  =  2 \pi \sqrt{\frac{2.7571}{10 .72 * 9.81 * 0.4392} }

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4 0
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lozanna [386]

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Explanation:

5 0
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