Attraction between polar molecules
Because there is only one stable ionic compound made up of potassium and chlorine, and that is KCl. So calling is "mono chloride" or similar would be redundant assuming you understand basic chemistry (i.e. knowing oxidation numbers of K is +1 and Cl is -1). When compounds can exist in multiple forms in nature like CO and CO2 you will preferably indicate it through the nomenclature, calling one a monoxide and the other a dioxide.
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<u>Volume </u><u>of</u><u> 106.9 mL from the concentrated solution should be taken and diluted to 350 </u><u>mL.</u>
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<u>We can use the </u><u>formula.</u><u> </u>
c1v1 =c2v2
<u>Where c1 is the concentration and v1 is volume of the concentrated </u><u>solution.</u><u> </u>
c2 is the concentration
and v2 is the volume of the diluted solution to be prepared
9.00 M x V1 = 2.75 M x 350 mL
V1 = 106.9 mL
<u>Volume of 106.9 mL from the concentrated solution should be taken and diluted to 350 </u><u>mL</u><u>.</u>
Answer:
The new volume is 5.37 L
Explanation:
Step 1: Data given
Initial volume = 10.0 L
Initial temperature = 22.0 °C
Initial pressure = 1.00 atm
Final temperature = 202 °C
Final pressure = 3.00 atm
Step 2: Calculate final volume
(P1*V1)/T1 = (P2*V2)/T2
⇒ with P1 = The initial pressure = 1.00 atm
⇒ with V1 = The initial volume = 10.0 L
⇒ with T1 = The initial temperature = 22 °C = 295 Kelvin
⇒ with P2 = The final pressure = 3.00 atm
⇒ with V2 = The final volume = TO BE DETERMINED
⇒ with T2 = The final temperature = 202 °C = 475 Kelvin
(1.00 * 10.0) / 295 = (3.00 * V2) / 475
10 / 295 = 3V2/ 475
3V2 = 4750/295
V2 = 5.37 L
The new volume is 5.37 L
