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lara31 [8.8K]
3 years ago
10

The halogens are the elements of group 17 on the periodic table. Halogens combine easily with elements from group 1. When a halo

gen reacts with a metal, what type of compound is formed?
A.
potassium
B.
salt
C.
noble gas
D.
alloy
Chemistry
2 answers:
Sonbull [250]3 years ago
4 0

Answer:

it was salt just took it

Explanation:

Yuki888 [10]3 years ago
3 0
D if i’m not mistaken
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The integrated rate law for a second-order reaction is given by:

\frac{1}{[A]t} =   \frac{1}{[A]0} + kt

where, [A]t= the concentration of A at time t,

[A]0= the concentration of A at time t=0

<span>k =</span> the rate constant for the reaction


<u>Given</u>: [A]0= 4 M, k = 0.0265 m–1min–1 and t = 180.0 min


Hence, \frac{1}{[A]t} = \frac{1}{4} + (0.0265 X 180)

<span>                                        = 4.858</span>

<span><span><span>Therefore, [A]</span>t</span>= 0.2058 M.</span>

<span>
</span>

<span>Answer: C</span>oncentration of A, after 180 min, is 0.2058 M

7 0
3 years ago
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In the formula XSO4 the symbol X could represent the element
Soloha48 [4]

Answer: X could represent the element of oxidation state (+2) such as (Mg2+, Pb2+, Ba2+, Ca2+, Ba2+, Zn2+, ....etc)

Explanation:

  • The formula of the compound XSO4 is a neutral compound that the algebraic summation of the oxidation states of different elements in it must be zero.
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On a weather map, which symbol on a line indicates a cold front? A. semicircle B. semicircles and triangles C. full circles D. t
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The bond that join the 3'-hydroxyl group of the deoxypentose of one nucleotide to the 5'-hydroxyl group of the deoxypentose of a
lara [203]

Answer:

phosphodiester bond

Explanation:

<em>Phosphodiester linkage/bond is found in deoxyribonucleic and ribonucleic acids. It is formed from a reaction involving the elimination of water from a reaction involving the hydroxyl groups of two different 5-carbon (pentose) sugars and a phosphate group.</em>

The elimination of water, also known as condensation reaction occur twice, resulting in the formation of two ester bonds which then bind the phosphate group to the pentose sugars to become a phosphodiester bond.

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8 0
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The specific heat of a certain type of metal is 0.128J/(g.°C). What is the final temperature if 305 J of hear is added to 28.8 g
klasskru [66]

Answer: Temperature final = 103 °C

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Next derive the equation to find final temperature

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Transpose T initial and change the sign so that T final will be left.

T final = Q / mc + T initial

Substitute the values:

T final = 305 J / 28.8 g x 0.128 J/(g°C)

= 305 J / 3.6864 J/°C

= 82.7 + 20.0°C

= 103 °C final temperature.

8 0
3 years ago
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