Answer:
Δt=0.85 seconds
Explanation:
In this chase the speed does not change as the mass change.So we can use the follow equation to find the required time
Δt=Δv/gμ
To stop the final speed will be zero therefore the change in speed will be
Δv= vf-vi
Δv=0-5 m/s
Δv= -5 m/s
Now we plug our values for Δv,g and μ to find time
Δt=Δv/gμ
Δt=(-5m/s) ÷(9.8m/s² × 0.6)
Δt=0.85 seconds
If their average velocity is 55 mph Northwest, they won't arrive in Santa Fe.
First of all, the straight-line distance from Houston to Santa Fe is only 740 miles. And if the headed out from Houston going northwest and maintained that heading, then they passed about 135 miles north of Santa Fe.
Let's just work with SPEED, OK ?
If they drove 881 miles at an average speed of 55 mi/hr, then
the trip took them
(881 mi) x (hr / 55 mi) = 16.018 hours (16 hrs 1 min)
Answer:
32500 kg m/s east, 42500 kg m/s west. Second car has larger momentum
Explanation:
The momentum of an object is given by
p = mv
where
m is the mass
v is the velocity
For the first car, m = 500 kg and v = 65 m/s east, so the momentum is
east
For the second car, m = 500 kg and v = 85 m/s west, so the momentum is
west
By comparing the two momentum, we see that the second car has larger momentum.
Answer:
15.8 seconds
Explanation:
Create an extended calculation to convert all the unit to what you need.
160 km 1000 m 1 hour 1 min
----------- x ------------- x -------------- x ---------- = 44.4 m/s
1 hour 1 km 60 min 60 sec
So 160km/hr is equal to 44.4m/s
Now you can figure out how many seconds it will take to go 700 meters.
44.4 m
---------- X x sec = 700 m
1 sec
Solve for x sec
x sec = 700m / 44.4 m/s
= 15.8 seconds
In this case, the movement is uniformly delayed (the final
rapidity is less than the initial rapidity), therefore, the value of the
acceleration will be negative.
1. The following equation is used:
a = (Vf-Vo)/ t
a: acceleration (m/s2)
Vf: final rapidity (m/s)
Vo: initial rapidity (m/s)
t: time (s)
2. Substituting the values in the equation:
a = (5 m/s- 27 m/s)/6.87 s
3. The car's acceleration is:
a= -3.20 m/ s<span>^2</span>