Answer:
a)
b)
Explanation:
a)
Using the conservation of energy between the moment when the bullet hit the block and the maximum compression of the spring.
Where:
- M is the bullet-block mass (0.00535 kg + 2.174 kg = 2.17935 kg)
- V is the speed of the system
- k is the spring constant (6.17*10² N/m)
- Δx is the compression of the spring (0.0634 m)
Then, let's find the initial speed of the bullet-block system.
b)
Using the conservation of momentum we can find the velocity of the bullet.
I hope it helps you!
Answer:
The angle between the diagonal and edge = 55 degrees
Explanation:
We will find it by finding the angle between two vectors (a and b)
We will assume it to be a unit cube
Vector a = (1,1,1) (defines the diagonal vector)
Vector b = (1,0,0) (defines the edge vector)
cos (theta) = (a.b)/(|a|*|b|)
theta = 54.74 degrees
theta = 55 degrees (Rounded to the nearest degree)
Answer:
The angle between the two vectors is 60°
Explanation:
Let A and B represent the two vectors, we have;
Let = a, = b, and = c
We have by cosine rule
c² = a² + b² - 2 × a × b × cos(C)
Where, the angle "C", is the angle between the resultant of the two vectors, a and b and facing the resultant
Given that, a = b = c, we have;
a² = a² + a² - 2 × a × a × cos(C)
a² = 2·a² - 2 × a² × cos(C)
2 × a² × cos(C) = 2·a² - a²
cos(C) = a²/(2·a²) = 1/2
Therefore, angle ∠C = arccosine(1/2) = 60°
The angle between the two vectors = ∠C = 60°.
I think it is d if not then im sorry