Answer: B>A=D>C
Explanation:
Kinetic Energy is the product of mass and square of the velocity
For Jogger A
For Jogger B
For Jogger C
For Jogger D
Kinetic Energy of Joggers in increasing order
B>A=D>C
To solve this problem we will start by considering how to calculate the apparent weight. On the sphere this will then be given that the real weight is the sum of the apparent weight and the Buoyant Force. Therefore we will have to
Here
= True Weight
= Apparent Weight
= Buoyant Force
If we seek to find the apparent weight we will have to,
Remember that
V = Volume (Volume Sphere)
= Density (At this case water density)
g = Gravitational acceleration
Therefore the apparent weight will be 0.1526N
Answer:
All of the above
Explanation:
Astronomers use all of those measures to classify stars. If you want to look more into classifying stars, check out the Hertzsprung-Russel Diagram. It covers how to identify red giants, main sequence, dwarf stars, ect. Distance from earth is typically measured in light years. The color of stars generally determines how hot they are. (Blue stars are the hottest) Also, the parallax method is used to measure stars that are closer to earth. This method relies heavily on geometry though.
Hope this helped!
SOLUTION:
Total amount of fruit = Total amount of apples + Total amount of pears + Total amount of oranges
Total amount of fruit = 15 / 4 + 29 / 4 + 81 / 8
Total amount of fruit = 30 / 8 + 58 / 8 + 81 / 8
Total amount of fruit = 169 / 8
Total amount of fruit = 21.125 kg
ANSWER:
Therefore, the chief bought 21.125 kg of fruit all together.
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Answer:
15.4 kg.
Explanation:
From the law of conservation of momentum,
Total momentum before collision = Total momentum after collision
mu+m'u' = V(m+m').................... Equation 1
Where m = mass of the first sphere, m' = mass of the second sphere, u = initial velocity of the first sphere, u' = initial velocity of the second sphere, V = common velocity of both sphere.
Given: m = 7.7 kg, u' = 0 m/s (at rest)
Let: u = x m/s, and V = 1/3x m/s
Substitute into equation 1
7.7(x)+m'(0) = 1/3x(7.7+m')
7.7x = 1/3x(7.7+m')
7.7 = 1/3(7.7+m')
23.1 = 7.7+m'
m' = 23.1-7.7
m' = 15.4 kg.
Hence the mass of the second sphere = 15.4 kg
