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2 years ago

What is the empirical formula for c12h24o6? what is the empirical formula for c12h24o6? ch2o cho c2h5o c2h4o cho2?

1 answer:

4 0

Empirical formula: The formula consist of proportions of the elements which is present in the compound or the simplest whole number ratios of atoms.

Now, molecular formula is equal to the product of n (ratio) and empirical formula.

Molecular formula = $n\times empirical formula$ (1)

molecular formula = $C_{12}H_{24}O_{6}$ (given)

Since, 6 is the smallest subscript in above molecular formula to get the simpler whole number of atoms. Therefore, divide all the subscripts i.e. number of carbon atoms (12), number of hydrogen atoms (24) and number of oxygen atoms (6) by 6.

empirical formula becomes $C_{2}H_{4}O$

Thus, according to the formula (1)

$C_{12}H_{24}O_{6} = 6\times C_{2}H_{4}O$

Hence, empirical formula of given molecular formula is $C_{2}H_{4}O$

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stiv31 [10]

Answer:

See explanation

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3 years ago

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8.3

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3 years ago

The equilibrium constant for the gas phase reaction

stellarik [79]

The equilibrium constant is found by [product]/[reactant]

If the equilibrium constant is very small, such as 4.20 * 10^-31, then that means at equilibrium there is very little product and a lot of reactant.
And likewise, if there is a lot of product formed, and very little reactant, then the K value will be very large, which tells us that it is predominantly product.

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At equilibrium, for your reaction, it is predominantly reactants.

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3 years ago

What volume does 0.482 mol of gas occupy at a pressure of 719 mmHg at 56 ∘C?

kozerog [31]

Answer:

The volume is 13, 69 L

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We use the formula PV=nRT. We convert the temperature in Celsius into Kelvin and the pressure in mmHg into atm.

0°C= 273K---> 56°C= 56 + 273= 329K

760 mmHg----1 atm

719 mmHg----x= (719 mmHgx 1 atm)/760 mmHg= 0,95 atm

PV=nRT ---> V= (nRT)/P

V=( 0,482 molx 0,082 l atm/K mol x 329K)/0,95 atm

7 0

3 years ago