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MaRussiya [10]
3 years ago
6

How would a scientist go about determining if an unknown substance is an element, compound, solution, or heterogeneous mixture?

Physics
1 answer:
stepan [7]3 years ago
5 0
<span>each of more than one hundred substances that cannot be chemically inter converted or broken down into simpler substances and are primary constituents of matter. Each element is distinguished by its atomic number, i.e., the number of protons in the nuclei of its atoms. thats part of one</span>
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Which of these phase changes requires energy?
frutty [35]

Answer:

A

Explanation:

You have to give energy away for B. You have to think about that carefully. The CO2 starts out with a great deal of energy (mostly KE) and has to slow down to go from gas to a solid. Not B

In general C is the same way. Water has more energy than ice. Not C

Same principle in D.  Not D.

So it's A

7 0
2 years ago
Whats the origin of all stars?<br> a) supernova<br> b) dwarfs<br> c) protostars<br> d) nebulae
Fudgin [204]
All stars originated from c., protostars. Protostars are the earliest phase of the process of star evolution.

-Starry Sky 

Oh lmao, my name and the irony. cx
5 0
3 years ago
Read 2 more answers
If an object has the same number of positive and negative changes, it’s electrical charge is ?
Marrrta [24]

The electrical charge is neutral. I hope this helps!

8 0
3 years ago
The first and second coils have the same length, and the third and fourth coils have the same length. They differ only in the cr
stealth61 [152]

Answer:

\frac{R_2}{R_1}=\frac{A_1}{A_2}\\\frac{R_4}{R_3}=\frac{A_3}{A_4}

Explanation:

The resistance of a conductor is directly proportional to its length and is inversely proportional to its cross-sectional area, this dependence is given by:

R=\frac{\rho L}{A}

\rho is the material's resistance, L is the legth and A is the cross-sectional area.

For the first and second coils, we have:

R_1=\frac{\rho L}{A_1}\\R_2=\frac{\rho L}{A_2}\\\rho L=R_1A_1\\\rho L=R_2A_2\\R_1A_1=R_2A_2\\\frac{R_2}{R_1}=\frac{A_1}{A_2}

For the third and fourth coils, we have:

R_3=\frac{\rho L'}{A_3}\\R_4=\frac{\rho L'}{A_4}\\\rho L'=R_3A_3\\\rho L'=R_4A_4\\R_3A_3=R_4A_4\\\frac{R_4}{R_3}=\frac{A_3}{A_4}

6 0
3 years ago
Light from a laser of wavelength λ1 shines normally on a pair of narrow slits separated by distance D. This results in a differe
lana66690 [7]

Answer:

Explanation:

The angular position of first intensity maxima is given by the expression

= λ / d where λ is wave length of light and d is slit separation

putting the values given in the problem. ,

.02 = λ₁ / D

Now wavelength has been increased to 2λ₁

angular separation of first maxima

=  2λ₁ /D

= 2 x .02

= .04 radians.

6 0
3 years ago
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