Answer:
1.34352 kg
Explanation:
= Mass of water falling = 1 kg
h = Height of fall = 0.1 km
= Change in temperature = 0.1
c = Specific heat of water = 4186 J/kg K
g = Acceleration due to gravity = 9.81 m/s²
= Mass of water in the vessel
Here the potential energy will balance the internal energy

Mass of the water in the vessel is 1.34352 kg
Answer:
23.49m
Explanation:
Distance = velocity x time
8.7 x 2.7 = 23.49m
Answer:
5.5 m/ sec
Explanation:
Because the inclined surface is frictionless so we can assume that total change of energy is zero
i-e ΔE = 0
Or we can say that difference between final and initial energy is zero i-e
Ef- Ei =0
Where,
Ef= final energy at the top of the ramp= KEf+PEf
Ei= Initial energy at the bottom of the ramp=KEi+PEi
So we have
(KEf+PEf)-(KEi+PEi)=0
==>KEf-KEi+PEf-PEi=0 -------------(1)
KEf = mgh = 200×9.8×h
Where h= Sin 22 = h/d= h/4.1
or
0.375×4.1=h
or h= 1.54 m
So, PEf= 200×9.8×1.54=3018.4 j
and KEf= 1/2 m
= 0.5×200×0=0 j
PEi= mgh = 200×9.8×0=0 j
KEi= 1/2 m
=0.5×200×
=100
j
Put these values in eq 1, we get;
0-100
+3018.4-0=0
-100
=-3018.4
==>
= 30.184
==> Vi = 
Answer:
48.7 J
Explanation:
For a mass-spring system, there is a continuous conversion of energy between elastic potential energy and kinetic energy.
In particular:
- The elastic potential energy is maximum when the system is at its maximum displacement
- The kinetic energy is maximum when the system passes through the equilibrium position
Therefore, the maximum kinetic energy of the system is given by:

where
m is the mass
v is the speed at equilibrium position
In this problem:
m = 3.6 kg
v = 5.2 m/s
Therefore, the maximum kinetic energy is:

Btu/(lb-°F) J/(g-°C i mean this is the correct answer