Answer:
=
Explanation:
given data:
Pressure P = 3 * 10^ 5 Pa
speed v = 5 m / s
Area A = A
from the information given in equation final Area is 1/3 of initial area i.e.
A ' = A / 3
we know that density of water = 1000 kg / m^ 3
from continuity equation
Av = A ' v'
so we have
speed v ' = 3*A*v / A
v ' = 3*A*5/ A
v = 15 m / s
from bernoulli's equation we can calculate final pressure
Required pressure P ' = P + ( 1/ 2) \rho [ v^ {2} v'^{ 2}]
=
=
=
=
Answer:
a) The strength of gravity decreases if one moved away from Jupiter
b) The strength of gravity increases if one fell into Jupiter
Explanation:
The gravitational attraction is given by Newton law of gravitation as follows;
Where;
G = The universal gravitational constant = 6.67408 × 10⁻¹¹ m³/(kg·s²)
M = The mass of Jupiter
m = The mass of the nearby body
R = The distance between the centers of Jupiter and the body
From the equation, we have that the gravitational strength varies inversely with the square of the separation distance between two bodies
Therefore, as one moves away, R increases, and the strength of gravity reduces
Similarly as the body falls into Jupiter, R, reduces the gravitational strength increases.