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Schach [20]
3 years ago
13

Select all that apply. The force that opposes the start of motion is referred to as _____.

Physics
2 answers:
77julia77 [94]3 years ago
8 0
The correct answers are <span>starting friction and </span>static friction

Friction slows down all forces, but starting friction slows down or stops completely the start of motion.

emmainna [20.7K]3 years ago
6 0

Answer: Option (c) is the correct answer.

Explanation:

A force helps to keep an object at rest is known as static friction. This type of friction avoids the movement of object from its initial place unless and until a larger force than the friction force is applied on the object.

Whereas sliding friction is the friction that is experienced when object is sliding. On the other hand, kinetic friction is the friction experienced when an object is moving from it initial place.

Thus, we can conclude that out of the given options the force that opposes the start of motion is referred to as static friction.

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The force of static friction keeps a stationary object at rest. Once the force of static friction is overcome, the force of kinetic friction is what slows down a moving object.
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Which of the following scientists taught physics in the United States?
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Oui

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Which is the correct answer?
Nezavi [6.7K]

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Point A

Explanation:

The work done by stretching or compressing a spring is given by E=1/2kx²

The potential energy is numerically equal to the work done.

This means that the higher the bigger the value of the extension, x, the higher the energy contained.

In this scenario the modulus of x is considered.

Among the given values of x the modulus of -5 is the largest.

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7 0
3 years ago
Newtons first law 1 to 5. <br>What is each of the net force for all of the 5 questions? ​
erica [24]

Answer:

1. 65 N.

2. 160 N.

3. 0 N.

4. 210 N.

5. 90 N.

Explanation:

1. Determination of the net force.

Force applied to the right (Fᵣ) = 80 N

Force applied to the left (Fₗ) = 145 N

Net force (Fₙ) =?

Fₙ = Fₗ – Fᵣ

Fₙ = 145 – 80

Fₙ = 65 N

Thus, the net force is 65 N

2. Determination of the net force.

Force 1 applied to the left (F₁) = 35 N

Force 2 applied to the left (F₂) = 125 N

Net force (Fₙ) =?

Fₙ = F₁ + F₂

Fₙ = 35 + 125

Fₙ = 160 N

Thus, the net force is 160 N.

3. Determination of the net force.

Force applied to the right (Fᵣ) = 75 N

Force applied to the left (Fₗ) = 75 N

Net force (Fₙ) =?

Fₙ = Fₗ – Fᵣ

Fₙ = 75 – 75

Fₙ = 0

Thus, the net force is 0 N

4. Determination of the net force.

Force 1 applied to the right (F₁) = 150 N

Force 2 applied to the right (F₂) = 60 N

Net force (Fₙ) =?

Fₙ = F₁ + F₂

Fₙ = 150 + 60

Fₙ = 210 N

Thus, the net force is 210 N.

5. Determination of the net force.

Force applied to the right (Fᵣ) = 115 N

Force applied to the left (Fₗ) = 25 N

Net force (Fₙ) =?

Fₙ = Fᵣ – Fₗ

Fₙ = 115 – 25

Fₙ = 90 N

Thus, the net force is 90 N

8 0
3 years ago
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