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2 years ago

Proses mendidihnya air.jelaskan!

Physics

1 answer:

inn [45]2 years ago

7 0

air akan mendidih pada suhu 100 derajat celcius.air akan selalu pada suhu tersebut,jika lebih dari itu air akan menguap

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Suppose you wanted to hold up an electron against the force of gravity by the attraction of a fixed proton some distance above i

Mice21 [21]

Answer:

r = 5.08 m

Explanation:

The electric force of attraction or repulsion is given by :

$F=\dfrac{kq_1q_2}{r^2}$

We need to find how far above the electron would the proton have to be if you wanted to hold up an electron against the force of gravity by the attraction of a fixed proton some distance above it.

So, the force from the proton is balanced by the mass of the electron.

$\dfrac{kq_pq_e}{r^2}=mg$

r is distance

$r=\sqrt{\dfrac{kq_pq_e}{mg}} \\\\r=\sqrt{\dfrac{9\times 10^9\times (1.6\times 10^{-19})^2}{9.11\times 10^{-31}\times 9.8}} \\\\r=5.08\ m$

So, proton have to be at a distance of 5.08 meters above the electron.

3 0

2 years ago

PLS HELP MEEEE (NO LINKS PLEASE)

-Dominant- [34]

I think it could be D please tell me if I’m wrong I hope you have a wonderful day ❤️

5 0

2 years ago

Read 2 more answers

The surface tension of isopropanol in air has a value of 23.00 units and the

Y_Kistochka [10]

Answer:

It's A & C

Explanation:

7 0

2 years ago

Read 2 more answers

A proton (mass=1.67x10^-27 kg, charge= 1.60x10^-19 C) moves from point A to point under the influence of an electrostatic force

Tom [10]

Answer:

$VB - VA = - 33.4$

Explanation:

Generally the workdone in moving the proton is mathematically represented as

$W = KE_f - KE_i$

Where $KE_i \ and \ KE_f \ are\ the\ initial \ and \ final \ kinetic \ energy$

$KE_i = \frac{1}{2} m v_a^2$

Here $v_a$ is the velocity at A with value 50 m/s

$KE_i = \frac{1}{2} (1.67*10^{-27}) * 50^2$

$KE_i = 2.09 *10^{-24} \ J$

Also

$KE_f = \frac{1}{2} m v_b^2$

Here $v_a$ is the velocity at A with value $80 km/s = 80000 m/s$

=> $KE_f = \frac{1}{2} (1.67*10^{-27}) * 80000^2$

=> $KE_f = 5.34 *10^{-18} \ J$

$W = 5.34 *10^{-18} - 2.09 *10^{-24}$

$W = 5.34 *10^{-18} m/s$

Now this workdone is also mathematically represented as

$W = q * V$

$q * V = 5.34 *10^{-18}$

Here $q = 1.60*10^{-19} C$

$V = \frac{5.34 *10^{-18} }{1.60*10^{-19}}$

$V = 33.4 \ V$

Generally proton movement is in the direction of the electric field it means that $VA>VB$

$VB - VA = - 33.4$

8 0

2 years ago

With an increase in temperature, the viscosity of liquids will: . (a) decrease (b) increase . (c) no change

ICE Princess25 [194]

Answer:

(a) decrease

Explanation:

Viscosity is the resistance which occur to flow of the fluid.

More the inter molecular forces between particles of the liquid, more the viscosity of liquid.

<u>Effect of temperature on viscosity:-</u>

Viscosity decreases with the increase in the temperature as forces among the particles decrease on increasing temperature. The kinetic energy of the particles of the liquid increases causing to move in more random motions and thus weaker inter molecular forces and this offer less resistance to the flow.

<u>Hence, viscosity of the liquids decrease with the increasing temperature.</u>

3 0

2 years ago