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miskamm [114]
2 years ago
13

An object has a displacement of 45

Physics
1 answer:
Anika [276]2 years ago
5 0

Answer:

45° to min.

1° ----> 60 min

45° ----> ?.

45 * 60

2700 min

<h3><u>2</u><u>7</u><u>0</u><u>0</u><u> </u><u>min</u></h3>
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Which occurrence demonstrates dispersion?
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A rainbow. Dispersion is the splitting of radiation into it's different wavelengths.
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Gantt charts are A. widely used network techniques. B. not widely used. C. planning charts used to schedule resources and alloca
kotykmax [81]

Answer:

planning charts used to schedule resources and allocate time is the correct answer

Explanation:

  • Gantt Charts are a project planning tool used to track the projects from the start to endpoint.
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A fly with a mass of 0.0025 kg flies at a rate of 20.0 m/s. What is the kinetic energy of the fly?
tamaranim1 [39]
KE = 0.5mV^2 = 0.5 * 0.0025 * (20)^2 = 
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Which of the following distances is the longest?a. 0.006 kilometers
zimovet [89]
820 meters is the longest

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If the solar system shrank so that the sun were located just one centimeter from Earth, about how far away could you find the ne
DedPeter [7]
E                  S                                                               *

The "E" represents Earth, "S" represent Sun, and the "*" represents the nearest star(which is Proxima Centauri).

The main thing to worry about here is units, so ill label everything out.
D'e,s'(Distance between earth and sun) = .<span>00001581 light years
D'e,*'(Distance between earth and Proxima) = </span><span>4.243 light years

Now this is where it gets fun, we need to put all the light years into centimeters.(theres alot)
In one light year, there are </span>9.461 * 10^17 centimeters.(the * in this case means multiplication) or 946,100,000,000,000,000 centimeters.

To convert we multiply the light years we found by the big number.
D'e,s'(Distance between earth and sun) = 1.496 * 10^13 centimeters<span>
D'e,*'(Distance between earth and Proxima) = </span><span>4.014 * 10^18 centimeters
</span>
Now we scale things down, we treat 1.496 * 10^13 centimeters as a SINGLE centimeter, because that's the distance between the earth and the sun. So all we have to do is divide (4.014 * 10^18 ) by (<span>1.496 * 10^13 ).
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As a result, you get a mere 268335.7 centimeters.

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A lot of my numbers came from google, so they are estimations and are not perfect, but its hard to be on really large scales.</span>
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