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kozerog [31]
3 years ago
14

Which temperature represents the highest average kinetic energy of the particles in a sample of matter ?

Chemistry
2 answers:
rusak2 [61]3 years ago
7 0
Answer:  [A]:  " 298 K " .
_____________________________________________
Note:

Answer choices:  [A]: 298 K = 24.85°C ;
                            [B]: 267 K = -6.15 °C ;
                            [C]:  27°C ;
                            [D]:  12°C ;
____________________________________________________
The highest temperature is answer choice:  [A]:  " 298 K " .
____________________________________________________
Genrish500 [490]3 years ago
3 0

Answer: Option C is correct.

Explanation: Average kinetic energy is directly proportional to the absolute temperature. Higher the temperature means higher the kinetic energy.

Average kinetic energy is given by:

K.E._{avg}=\frac{3kT}{2}

Where, k = Boltzman constant

T = Temperature

We are given different temperatures, so to compare they all should have the same units.

a) 298K

b) 267K

c) 27°C = 273+27 = 300K

d) 12°C = 273+12 = 285K

Looking at the temperature values, C part will have the highest average kinetic energy.

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The distance between two points on a map is 0.04 kilometers what is the distance in meters
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A 3.50 g sample of an unknown compound containing only C , H , and O combusts in an oxygen‑rich environment. When the products h
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Explanation:

First, calculate the moles of CO_{2} using ideal gas equation as follows.

                PV = nRT

or,          n = \frac{PV}{RT}

                = \frac{1 atm \times 4.41 ml}{0.0821 Latm/mol K \times 293 K}      (as 1 bar = 1 atm (approx))

                = 0.183 mol

As,   Density = \frac{mass}{volume}

Hence, mass of water will be as follows.

                Density = \frac{mass}{volume}

             0.998 g/ml = \frac{mass}{3.26 ml}    

                 mass = 3.25 g

Similarly, calculate the moles of water as follows.

        No. of moles = \frac{mass}{\text{molar mass}}

                              =  \frac{3.25 g}{18.02 g/mol}            

                              = 0.180 mol

Moles of hydrogen = 0.180 \times 2 = 0.36 mol

Now, mass of carbon will be as follows.

       No. of moles = \frac{mass}{\text{molar mass}}

          0.183 mol =  \frac{mass}{12 g/mol}            

                              = 2.19 g

Therefore, mass of oxygen will be as follows.

              Mass of O = mass of sample - (mass of C + mass of H)

                                = 3.50 g - (2.19 g + 0.36 g)

                                = 0.95 g

Therefore, moles of oxygen will be as follows.

          No. of moles = \frac{mass}{\text{molar mass}}

                               =  \frac{0.95 g}{16 g/mol}            

                              = 0.059 mol

Now, diving number of moles of each element of the compound by smallest no. of moles as follows.

                         C              H           O

No. of moles:  0.183        0.36       0.059

On dividing:      3.1           6.1            1

Therefore, empirical formula of the given compound is C_{3}H_{6}O.

Thus, we can conclude that empirical formula of the given compound is C_{3}H_{6}O.            

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Answer:

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Explanation:

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=420j

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