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3 years ago

What happens to an electron when energy is added?

1 answer:

7 0

When an electron is hit by a photon of light, it absorbs the quanta of energy the photon was carrying and moves to a higher energy state. One way of thinking about this higher energy state is to imagine that the electron is now moving faster, (it has just been "hit" by a rapidly moving photon).

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Security is a major concern now that computers play such a large part in healthcare. To address this concern, as well as others

Fed [463]

The correct answer is C. HIPAA

This is the acronym for Health Insurance Portability and Accountability Act. This was done to prevent illegal disclosing of data which was stored in computers and was passed in 1996 when it was signed by the then incumbent president Bill Clinton.

6 0

4 years ago

Read 2 more answers

Select the correct answer. x y 2.5 6.25 9.4 88.36 15.6 243.63 19.5 380.25 25.8 665.64 The table lists the values for two paramet

In-s [12.5K]

Answer: B. 16

Explanation:

The given table:

x y

2.5 6.25

9.4 88.36

15.6 243.63

19.5 380.25

25.8 665.64

Here, we observed that value of y is the square value of x.

i.e. $y=x^2$ [For example 2.5²=6.25, 9.4²=88.36, 15.6²=243.63]

Put x=4, we get

$y=4^2=16$

Hence, the approximate value of y for x = 4 is 16.

So, the correct option is B. 16 .

6 0

3 years ago

Particle A of charge 3.06 10-4 C is at the origin, particle B of charge -5.70 10-4 C is at (4.00 m, 0), and particle C of charge

Alex

Answer:

F_net = 26.512 N

Explanation:

Given:

Q_a = 3.06 * 10^(-4 ) C

Q_b = -5.7 * 10^(-4 ) C

Q_c = 1.08 * 10^(-4 ) C

R_ac = 3 m

R_bc = sqrt (3^2 + 4^2) = 5m

k = 8.99 * 10^9

Coulomb's Law:

F_i = k * Q_i * Q_j / R_ij^2

Compute F_ac and F_bc :

F_ac = k * Q_a * Q_c / R^2_ac

F_ac = 8.99 * 10^9* ( 3.06 * 10^(-4 ))* (1.08 * 10^(-4 )) / 3^2

F_ac = 33.01128 N

F_bc = k * Q_b * Q_c / R^2_bc

F_bc = 8.99 * 10^9* ( 5.7 * 10^(-4 ))* (1.08 * 10^(-4 )) / 5^2

F_bc = - 22.137 N

Angle a is subtended between F_bc and y axis @ C

cos(a) = 3 / 5

sin (a) = 4 / 5

Compute F_net:

F_net = sqrt (F_x ^2 + F_y ^2)

F_x = sum of forces in x direction:

F_x = F_bc*sin(a) = 22.137*(4/5) = 17.71 N

F_y = sum of forces in y direction:

F_y = - F_bc*cos(a) + F_ac = - 22.137*(3/5) + 33.01128 = 19.72908 N

F_net = sqrt (17.71 ^2 + 19.72908 ^2) = 26.5119 N

Answer: F_net = 26.512 N

5 0

4 years ago

An expensive vacuum system can achieve a pressure as low as 1.00 × 10 − 8 N / m 2 at 19.5 °C . How many atoms are there in a cub

Stels [109]

Answer:

2475042

Explanation:

P = Pressure = [/tex]1\times 10^{-8}\ N/m^2[/tex]

V = Volume = 1 cm³

T = Temperature = 19.5 °C

R = Gas constant = 8.341 J/mol K

$N_A$ = Avogadro's number = $6.022\times 10^{23}$

n = Amount of substance

From ideal gas law we have

$PV=nRT\\\Rightarrow n=\frac{PV}{RT}\\\Rightarrow n=\frac{1\times 10^{-8}\times 1\times 10^{-6}}{8.314(273.15+19.5)}\\\Rightarrow n=4.11\times 10^{-18}$

Number of atoms is given by

$n\times N_A\\ =4.11\times 10^{-18}\times 6.022\times 10^{23}\\ =2475042\ atoms$

The number of atoms in this vacuum is 2475042

8 0

3 years ago

What is the force on a 52 coulomb charge in a field of 5 N/C

slega [8]

Https://courses.physics.illinois.edu/phys102/sp2013/lectures/lecture2.pdf

Check out upload.

Download pdf

8 0

3 years ago