Answer:
the length of the wire is 134.62 m.
Explanation:
Given;
resistivity of the copper wire, ρ = 2.6 x 10⁻⁸ Ωm
cross-sectional area of the wire, A = 35 x 10⁻⁴ cm² = ( 35 x 10⁻⁴) x 10⁻⁴ m²
resistance of the wire, R = 10Ω
The length of the wire is calculated as follows;
Therefore, the length of the wire is 134.62 m.
We are given that a 500 kg object is hanging from a spring. To determine the amount the spring is stretched we will use Hook's law, which states the following:
Where:
Since the object is hanging the only force acting on the spring is the weight of the object. The weight of the object is:
Where:
Plugging in the values we get:
Solving the operations:
Now we solve for "x" from Hook's law by dividing both sides by "k":
Now we plug in the known values:
Solving the operations:
Therefore, the spring is stretched by 5.4 meters.
Answer:
The correct answer is "21195 N".
Explanation:
The given values are:
Tensile strength,
= 3000 MN/m²
Diameter,
= 3.0 mm
i.e.,
= 3×10⁻³ m
Now,
The maximum load will be:
=
On substituting the values, we get
=
=
=