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mario62 [17]
3 years ago
12

Ice that formed thousands of years ago is often found to contain tiny bubbles of gas. this gas came from __________. ice that fo

rmed thousands of years ago is often found to contain tiny bubbles of gas. this gas came from __________. the atmosphere tiny zooplankton that lived in the water before it froze water vapor released from melting ice tiny phytoplankton that lived in the water before it froze
Physics
1 answer:
motikmotik3 years ago
8 0
Atmosphere

Atmospheric gas from prehistoric eras is found trapped in glaciers in the form of bubbles. These gas bubbles are the basis of studying ice cores as they provide us with accurate estimates of the conditions of past climates. The bubbles allow us to determine the composition of atmospheric air, such as the carbon dioxide and methane concentrations, as well as allow us to determine air temperatures in the past.
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Someone please help !!
masha68 [24]
I’m pretty sure it’s c.... hope it helps and hope it’s right.
7 0
3 years ago
The photeselestric effect is observed when light of a sufficiently high frequency is focused onto a polished metal surface, emit
Helga [31]

Answer:

3.4\cdot 10^{-19} J

Explanation:

In order to convert the work function of cesium from electronvolts to Joules, we must use the following conversion factor:

1 eV = 1.6 \cdot 10^{-19} J

In our problem, the work function of cesium is

E=2.1 eV

so, we can convert it into Joules by using the following proportion:

1 eV : 1.6\cdot 10^{-19} J = 2.1 eV : x\\x=\frac{(1.6\cdot 10^{-19} J)(2.1 eV)}{1 eV}=3.4\cdot 10^{-19} J

8 0
3 years ago
A spinning tossed baseball veers off course in the direction ofA) reduced air pressure on the ball.B) increased air pressure on
katovenus [111]

Answer:

A) reduced air pressure on the ball.

Explanation:

3 0
3 years ago
Define reversible change​
inysia [295]

A reversible change is a change that can be undone or reversed

8 0
3 years ago
Please. Physics is so difficult.
Softa [21]

Answer:

0.010 m

Explanation:

So the equation for a pendulum period is: y=2\pi\sqrt{\frac{L}{g}} where L is the length of the pendulum. In this case I'll use the approximation of pi as 3.14, and g=9.8 m\s. So given that it oscillates once every 1.99 seconds. you have the equation:

1.99 s = 2(3.14)\sqrt{\frac{L}{9.8 m\backslash s^2}}\\

Evaluate the multiplication in front

1.99 s = 6.28\sqrt{\frac{L}{9.8m\backslash s^2}

Divide both sides by 6.28

0.317 s= \sqrt{\frac{L}{9.8 m\backslash s^2}}

Square both sides

0.100 s^2= \frac{L}{9.8 m\backslash s^2}

Multiply both sides by m/s^2  (the s^2 will cancel out)

0.984 m = L

Now now let's find the length when it's two seconds

2.00 s = 6.28\sqrt{\frac{L}{9.8m\backslash s^2}}

Divide both sides by 6.28

0.318 s = \sqrt{\frac{L}{9.8 m\backslash s^2}

Square both sides

0.101 s^2 = \frac{L}{9.8 m\backslash s^2}

Multiply both sides by 9.8 m/s^2 (s^2 will cancel out)

0.994 m = L

So to find the difference you simply subtract

0.984 - 0.994 = 0.010 m

4 0
2 years ago
Read 2 more answers
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