Answer:
39.40 MeV
Explanation:
<u>Determine the minimum possible Kinetic energy </u>
width of region = 5 fm
From Heisenberg's uncertainty relation below
ΔxΔp ≥ h/2 , where : 2Δx = 5fm , Δpc = hc/2Δx = 39.4 MeV
when we apply this values using the relativistic energy-momentum relation
E^2 = ( mc^2)^2 + ( pc )^2 = 39.4 MeV ( right answer ) because the energy grows quadratically in nonrelativistic approximation,
Also in a nuclear confinement ( E, P >> mc )
while The large value will portray a Non-relativistic limit as calculated below
K = h^2 / 2ma^2 = 1.52 GeV
Answer:
150 J
Explanation:
Work: This can be defined as the product of force and distance. The S.I unit of work is Joules (J)
The work done in lifting the crate = Force × distance.
W = F×d .............................. Equation 1.
Where F = force, d = distance, W = work done in lifting the crate,
Given: F = 100 N, d = 1.5 m.
Substituting these values into equation 1
W = 100(1.5)
W = 150 J.
Thus the work done in lifting the crates to that height is 150 J
An alpha particle is identical to a helium nucleus ... 2 protons, 2 neutrons. <em>(1)</em>
Answer:
Right now Pluto is classified as a <em>dwarf planet.</em>
Explanation: