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lilavasa [31]
4 years ago
9

What is the mass of a CuCl2 sample if it contains 0.172 moles of the compound?

Chemistry
1 answer:
Delvig [45]4 years ago
5 0

Answer:

Mass of  CuCl₂ = 23.125 g

Explanation:

Given data:

Number of moles of CuCl₂ = 0.172 mol

Mass of CuCl₂ = ?

Solution:

First of all we will calculate the molar mass of CuCl₂.

Molar mass of CuCl₂ = 63.546 + 2(35.5)

Molar mass of CuCl₂ = 134.45 g/mol

Formula:

Number of moles = mass / molar mass

Mass =  Number of moles × molar mass

Mass =  0.172 mol × 134.45 g/mol

Mass = 23.125 g

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Copper metal reacts with hot concentrated sulfuric acid solution to form aqueous copper(ii) sulfate, sulfur dioxide gas, and wat
Alex777 [14]
The unbalanced chemical equation with the corresponding phase for each substance is shown below: 

Cu₍s₎ + H₂SO₄₍aq₎ → CuSO₄₍aq₎ + SO₂₍g₎ + H₂O₍l₎

The copper metal is solid, the sulfuric acid and copper sulfate are in aqueous solution. Water is in the liquid phase while sulfur dioxide is in the gas phase. 

In order to obtain the balanced equation, we must ensure that the number of atoms present in the reactant side is equal to that in the product side. First, we list the elements involved and count their number on each side.

Reactant           Product
   1             Cu      1
   2              H       2
   1              S       2
   4              O       5

To balance the equation, we need to have 2 moles of H₂SO₄ and 2 moles of H₂O. The balanced chemical equation is then:

Cu₍s₎ + 2H₂SO₄₍aq₎ → CuSO₄₍aq₎ + SO₂₍g₎ + 2H₂O₍l₎

Reactant           Product
   1             Cu      1
   4              H       4
   2              S       2
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3 0
3 years ago
Pls help me with this question thank you
klemol [59]
Mass times acceleration
6 0
3 years ago
A gaseous mixture at 265K and 1.0 atm contains 25 O2 60 N2 and 15 CO2 mole basis The velocities of the components are 0.084 cm s
Free_Kalibri [48]

Answer:

The molar average velocity is 0.0588 cm/s

The N₂ diffusion velocity relative to the mole average velocity is -0.1428 cm/s

The molar diffusional flux of N₂ is -3.9x10⁻³

Explanation:

Given data:

T = temperature = 265 K

O₂ = 25%

N₂ = 60%

CO₂ = 15%

vO₂ = -0.084 cm/s

vN₂ = 0.12 cm/s

vCO₂ = 0.052 cm/s

The molar average velocity is equal:

v_{av} =(0.25*(-0.084))+(0.6*0.12)+(0.15*0.052)=0.0588cm/s

The N₂ diffusion velocity relative to the molar average velocity is:

v_{i} -v_{av} =-0.084-0.0588=-0.1428cm/s

The molar diffusional flux of N₂ is:

N_{N_{2} } =\frac{P}{RT} y_{A} (v_{i} -v_{av} )=-3.9x10^{-3}

8 0
4 years ago
What is the formula for Aluminum iodate?
Y_Kistochka [10]

Answer:

the formula is AlI3

6 0
3 years ago
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