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vaieri [72.5K]
3 years ago
5

A cylinder with a mass of 98 grams is made of copper (density 8.94 g/cm³). If the radius of the cylinder is 2.0 cm, what is the

height of this object in cm?
Chemistry
1 answer:
sasho [114]3 years ago
7 0

The height of the described cylinder is 0.85 cm

Mass= 98g

Density= 8.9g/cm^3

Density= (mass/volume)

Substitute the values

8.94= 98/ volume

Volume= \frac{98}{8.94}

Volume= 10.97cm^{3}

Volume of a cylinder can be found with (V = π r 2 h.)

h= height of cylinder ?

radius= 2cm

Substitute the values

10.97= π × 2^{2} × h

h= 10.97/12.57

h= 0.85 cm

Therefore, height of the described cylinder is 0.85 cm

Learn more at : brainly.com/question/21667661?referrer=searchResults

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raketka [301]

Answer:

It works because of the significant principle of piezoelectricity

Explanation:

7 0
4 years ago
Which of these expressions are correct variations of the Combined Gas Law?
mafiozo [28]

Answer:

Both

Explanation:

The combined gas law is also known as the general gas law.

From the ideal gas law we assume that n = 1;

So;

              PV  = nRT

 and then;

                  \frac{P_{1}V_{1}  }{T_{1} }  = \frac{P_{2}V_{2}  }{T_{2} }

   If we cross multiply;

                P₁V₁T₂   = P₂V₂T₁

  So;

         T₁ = T_{2} \frac{P_{1}V_{1}  }{P_{2} V_{2} }

Also;

         V₂  = V_{1} \frac{P_{1} T_{2} }{P_{2} T_{1} }

So from the choices both are correct

3 0
3 years ago
1 C8H10(l) +21/2O2(g) → 8CO2(g) + 5H2O(g), Hcomb= ? Hf for C8H10(l) = +49.0kJ/mol C8H10(l) Use the balanced combustion reaction
nikklg [1K]

Answer:

H_{comb}=-4406kJ/mol

Explanation:

Hello,

In this case, the enthalpy of combustion is understood as the energy released when one mole of fuel, in this case octene, is burned in the presence of oxygen and is computed with the enthalpies of formation of the fuel, carbon dioxide and water as shown below (oxygen is circumvented as it is a pure element):

H_{comb}=8*\Delta _fH_{CO_2}+5\Delta _fH_{H_2O}-\Delta _fH_{C_8H_{10}}

Thus, since we already know the enthalpy of combustion of the fuel, for carbon and water we have -393.5 and -241.8 kJ/mol respectively, thereby, the enthalpy of combustion turns out:

H_{comb}=8*(-393.5kJ/mol)+5(-241.8kJ/mol)-49.0kJ/mol\\\\H_{comb}=-4406kJ/mol

Best regards.

4 0
3 years ago
Which organic prefix is matched with the number of carbon atoms that it represents?
Mandarinka [93]

Answer:heat-,7

Explanation:According to table P, heat- is an organic prefix used to represent 7 carbon atoms

8 0
3 years ago
IUPAC NAME FOR:<br>CH2(OH)-CH2-CH(C2H5)-OH
fgiga [73]

The IUPAC name for the organic compound CH2(OH)-CH2-CH(C2H5)-OH is Pentan-1,3-diol

This compound above belong to class of organic compound called the alkanols

<h3>What are organic compounds?</h3>

Organic compounds are compounds which contains carbon and hydrogen only.

Some few classes of organic compounds includes the following:

  • Alkanes
  • Alkenes
  • Alkynes
  • Alkanols
  • Alkanals
  • Alkanones
  • Esters
  • Ketones and other

So therefore, the IUPAC name for the organic compound is CH2(OH)-CH2-CH(C2H5)-OH is Pentan-1,3-diol

Learn more about organic compounds:

brainly.com/question/704297

#SPJ1

6 0
2 years ago
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