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vaieri [72.5K]
2 years ago
5

A cylinder with a mass of 98 grams is made of copper (density 8.94 g/cm³). If the radius of the cylinder is 2.0 cm, what is the

height of this object in cm?
Chemistry
1 answer:
sasho [114]2 years ago
7 0

The height of the described cylinder is 0.85 cm

Mass= 98g

Density= 8.9g/cm^3

Density= (mass/volume)

Substitute the values

8.94= 98/ volume

Volume= \frac{98}{8.94}

Volume= 10.97cm^{3}

Volume of a cylinder can be found with (V = π r 2 h.)

h= height of cylinder ?

radius= 2cm

Substitute the values

10.97= π × 2^{2} × h

h= 10.97/12.57

h= 0.85 cm

Therefore, height of the described cylinder is 0.85 cm

Learn more at : brainly.com/question/21667661?referrer=searchResults

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Hello!

The half-life is the time of half-disintegration, it is the time in which half of the atoms of an isotope disintegrate.

We have the following data:

mo (initial mass) = 53.3 mg

m (final mass after time T) = ? (in mg)

x (number of periods elapsed) = ?

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Let's find the number of periods elapsed (x), let us see:

T = x*P

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25.9 = 10.0\:x

10.0\:x = 25.9

x = \dfrac{25.9}{10.0}

\boxed{x = 2.59}

Now, let's find the final mass (m) of this isotope after the elapsed time, let's see:

m =  \dfrac{m_o}{2^x}

m =  \dfrac{53.3}{2^{2.59}}

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\boxed{\boxed{m \approx 8.85\:mg}}\end{array}}\qquad\checkmark

I Hope this helps, greetings ... DexteR! =)

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