When going down a group the no of orbits increases. That is n value increases (n=principle quantum number). When the number of atomic orbitals increases, the radius gradually increases. (going down the group means the number of obits that electrons can fill will increase)
And the atomic radius from left to right in the periodic table actually DECREASES. That is due to increase in electronegetivity to the right side of the periodic table.
Explanation:
maltose is your answer
hope it's helpful for you
This question is incomplete, the complete question is;
The area of the gold electrodes on the quartz crystal microbalance at the opening of Chapter 2 is 3.3 mm^2. One gold electrode is covered with DNA at a surface density of 1.2 pmol/cm2.
(a) How much mass of the nucleotide cytosine (C) is bound to the surface of the electrode when each bound DNA is elongated by one unit of C. The mass formula mass of the bound nucleotide is cytosine + deoxyribose + phosphate = C9H10N3O6P = 287.2 g/mol
Answer: mass of the nucleotide (c) bound is 11.37 g
Explanation:
Given that the area of gold electrodes = 3.3 mm^2
surface density of one gold electrode = 1.2 pmol/cm^2
that is to that in every 1 cm^2 of area, 1.2 pmol DNA is present
therefore
mass of nucleotide present in 3.3 mm^2 is;
= (1.2/100 * 3.3) pmol
= 0.0396 pmol
we were given that formula mass of the bound nucleotide = 287.2 g/mol
so
mass of the nucleotide (c) bound = ( 287.2 * 0.0396 )g
mass of the nucleotide (c) bound = 11.37 g
Search up “Chemistry, how to do empirical formulas” a guy named Tyler Dewitt is really good at explaining
Answer:
The answer is option d.
Ka = (H+)(H2PO4-)/(H3PO4)
Hope this helps.
