Im pretty sure it’s a because it makes more sense you know?.
<span>the answer would be 3,959 miles</span>
844J.
Assuming that there were no encumbrances during it's foreswing and it reached it's full potential at apogee.
Take into account that in a standing wave, the frequency f of the points executing simple harmonic motion, is simply a multiple of the fundamental harmonic fo, that is:
f = n·fo
where n is an integer and fo is the first harmonic or fundamental.
fo is given by the length L of a string, in the following way:
fo = v/λ = v/(L/2) = 2v/L
becasue in the fundamental harmonic, the length of th string coincides with one hal of the wavelength of the wave.
Answer:
The correct answer is "22.27 hours".
Explanation:
Given that:
Radioactive isotope activity,
= 490,000 Bq
Activity,
= 110,000 Bq
Time,
= 48 hours
As we know,
⇒ 
or,
⇒ 
By taking "ln", we get
⇒ 
By substituting the values, we get
⇒ 
⇒ 
As,
⇒ 
then,
⇒ 
⇒ 
