We are given the following:
thickness, T = 0.155 mm
charge-carrier density, n = 1.05 x 10^25 / m3
current, I = 2.67 A
voltage, V = 4.89 mV
We are asked to get the magnetic strength, B
To solve this, we use the Hall Effect formula:
V = - IB / neT
where e is the charge of an electron which is e = 1.60 x 10^-19 and B is the magnetic field
Rearranging the formula
B = -V n e T / I
Substituting the given values
B = - (4.89 x 10^-3 V) (1.05 x 10^25 / m3) (0.155 x 10^-3 m) / 2.67 A
B = -2.98 x 10^18 Teslas
Answer:
The direction and magnitude of velocity is 38.65° and 12.005 m/s
Explanation:
Given that,
Mass of car = 1500 kg
Speed of car = 25.0 m/s
Mass of van = 2500 kg
Speed of van =20.0 m/s
We need to calculate the velocity
Using conservation of energy
The magnitude of velocity
We need to calculate the direction
Hence, The direction and magnitude of velocity is 38.65° and 12.005 m/s.
Using the formula t=root of 2h/g then where h=28 and g=9.8 then substitute so the answer is 2.4seconds
The measurements used in the experiment is the amount of speed over time.
The measurement of speed is indicated along the “y” axis.
Upon viewing the graph, the highest point along the “y” axis shown is 25 m/s. This would be the maximum.
The maximum speed of the car would be 25 m/s.
