Yes, they look exactly like newborn babies
Answer:
a. Weight of Object in Water = 20 N
b. Up thrust = 20 N
c. Weight of Water Displaced = 20 N
Explanation:
a.
The weight of the object remains same in the water as well. Because, the same force of gravity is acting there as well. Hence,
<u>Weight of Object in Water = 20 N</u>
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b.
Since, the object floats on the water. Therefore, according to Archimedes' principle the up thrust force acting on the object must be equal to the weight of object:
Up thrust = Weight of object
<u>Up thrust = 20 N</u>
<u></u>
c.
From Archimedes' Principle, we know that the up thrust or the Buoyant force is equal to the weight of the water displaced by the object. therefore:
Weight of Water Displaced = Up thrust
<u>Weight of Water Displaced = 20 N</u>
Answer:
9080 N
Explanation:
Consider the two motions of the ball.
In the downward motion, initial velocity, <em>u</em>, is 0 (because it falls from rest) and the distance is 28.7 m. Using the equation of motion and using <em>g</em> as 9.8 m/s²,
<em>v² = u² + 2as</em>
<em>v² = </em>0² + 2 × 9.8 × 28.7<em> </em>= 562.52
<em>v = </em>19.7 m/s
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For the downward motion, the initial velocity is unknown, the final velocity is 0 and initial velocity is desired. <em>g</em> is negative because the motion is upwars.
<em>0² = v² - </em>2 × 9.8 × 19.8
<em>v² = </em>388.08
<em>v = </em>10.7 m/s
The change in momentum = 0.502(10.7 -(23.7)) = 21.7868 kgm/s
The impulse = change in monetum
Ft = 21.7868 kgm/s
But t = 2.4 ms
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Let's look at the equation for momentum (p)

Where p is the momentum, m is the mass and v is the velocity.
If an object doubles in mass then we have 2m and so:

If it doubles in mass, then the momentum is also doubled.
Brainliest will be much appreciated!