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mel-nik [20]
3 years ago
15

A chain lying on the ground is 11 meters long and its mass is 95 kilograms. The chain is threaded through a pulley, which is fix

ed to the ground, and pulled directly up so that it forms the shape of an L. How much work is required to raise one end of the chain to a height of 7 meters?
Physics
1 answer:
Natalija [7]3 years ago
6 0

Answer: 296.1 J or 6.98 kJ

Explanation:

Given

Length of chain, l = 11 m

Mass of chain, m = 95 kg

It is worthy of note that chain has two ends. So this depends which of the two ends should end up at

the given height of 7 m.

Scenario 1. If it is the leading end:

Weight of chain raised

W = mg/l

W = 9.8×95/11

W = 84.6 N

Height raised = ½ m (which is the height of the centre of gravity of the raised portion).

Work done = 84.6 × 1/2 * 7 = 296.1 Joules

Scenario 2. If it is the trailing end:

Weight of chain raised = 9.8×95 = 931 N.

Height raised (average) = 12.5 m (5.5 m for the chain midpoint + 7 m off the ground)

Work done = 931 × 7.5 = 6.98 kJoules

Thus, the work required is either of 296.1 J or 6.98 kJ

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Nuclide X has a higher rate of decay than nuclide Y. Based on this information, which of the following statements must be true?
marshall27 [118]

Answer: Answer down below.

Explanation:

8 0
2 years ago
__________ research is designed to measure the association between variables that are not manipulated by the researcher.
Sliva [168]

Answer:

Option c. Correlational

Explanation:

Correlational research is basically a method of carrying out a research where an experiment can not be conducted and where a researcher has to figure out that whether the two variable are in association with each other and if these are related then in what way the association between these two exists without any manipulation from the researcher's end.

It seeks to understand, measure and make assessment of the relationship or  

association between these variables but can not find out if a variable is caused by the other variable.

3 0
4 years ago
How far did a frog jump if he travels at a rate of 2.1 m/s for 10 seconds?
Anestetic [448]

Answer:

21 m

Explanation:

The motion of the frog is a uniform motion (constant speed), therefore we can find the distance travelled by using

d=vt

where

d is the distance covered

v is the speed

t is the time

The frog in this problem has a speed of

v = 2.1 m/s

and therefore, after t = 10 s, the distance it covered is

d=(2.1)(10)=21 m

3 0
3 years ago
A circular loop of wire of area 10 cm^2 carries a current of 25 A. At a particular instant, the loop lies in the xy-plane and is
S_A_V [24]

The magnetic dipole moment of the current loop is  0.025 Am².

The magnetic torque on the loop is 2.5 x 10⁻⁴  Nm.

<h3>What is magnetic dipole moment?</h3>

The magnetic dipole moment of an object, is the measure of the object's tendency to align with a magnetic field.

Mathematically, magnetic dipole moment is given as;

μ = NIA

where;

  • N is number of turns of the loop
  • A is the area of the loop
  • I is the current flowing in the loop

μ = (1) x (25 A) x (0.001 m²)

μ = 0.025 Am²

The magnetic torque on the loop is calculated as follows;

τ = μB

where;

  • B is magnetic field strength

B = √(0.002² + 0.006² + 0.008²)

B = 0.01 T

τ = μB

τ =  0.025 Am² x 0.01 T

τ = 2.5 x 10⁻⁴  Nm

Thus, the magnetic dipole moment of the current loop is determined from the current and area of the loop while the magnetic torque on the loop is determined from the magnetic dipole moment.

Learn more about magnetic dipole moment here: brainly.com/question/13068184

#SPJ1

8 0
1 year ago
An ambulance is traveling north at 55.9 m/s, approaching a car that is also traveling north at 28.4 m/s. The ambulance driver he
wlad13 [49]

Answer:

915 Hz

Explanation:

The observed frequency from a sound source is given as

f₀ = f [(v + v₀)/(v+vₛ)]

where

f₀ = observed frequency of the sound by the observer = ?

f = actual frequency of the sound wave = 983 Hz

v = actual velocity of the sound waves = 343 m/s

vₛ = velocity of the source of the sound waves = 55.9 m/s

v₀ = velocity of the observer = 28.4 m/s

f₀ = 983 [(343+28.4)/(343+55.9)]

f₀ = 915.2 Hz = 915 Hz

6 0
3 years ago
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