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Lunna [17]
3 years ago
10

At resonance, what is impedance of a series RLC circuit?

Physics
1 answer:
likoan [24]3 years ago
5 0

Answer:

Impedance Z given as

Z=\sqrt{(X_C^2-X_L^2)+R^2}

At resonance

X_C=X_L

Z=\sqrt{(X_C^2-X_C^2)+R^2}

Z=R

At the resonance condition the impedance of a series RLC  will be equal to the R.

---------------------------------------------------------------------------------------------

The quality factor of the circuit depends on R ,L ,C and width of the resonance.

Quality factor Q

Q=\dfrac{f}{BW}

BW= Band width

f=Frequency at resonance

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For the wave of light you generated in the Part B, calculate the amount of energy in 1.0 mol of photons with that same frequency
Angelina_Jolie [31]

Answer:

2.7 J

Explanation:

The energy of one photon is given by

E=hf

where

h is the Planck constant

f is the frequency

For the photons in this problem,

f=6.8\cdot 10^9 Hz

So the energy of one photon is

E_1=(6.63\cdot 10^{-34})(6.8\cdot 10^9 )=4.5\cdot 10^{-24} J

The number of photons contained in 1.0 mol is

N_A = 6.022\cdot 10^{23} mol^{-1} (Avogadro number)

So the total energy of N_A photons contained in 1.0 mol is

E=N_A E_1 =(6.022\cdot 10^{23})(4.5\cdot 10^{-24})=2.7 J

3 0
3 years ago
Look at the diagrams. Each model the arrangement of particles in a substance.
Kisachek [45]

Answer:

a

Explanation:

because it has  compact  molecules  

5 0
2 years ago
The angle of incidence for a ray of light passing through the centre of curvature of a concave mirror is.
evablogger [386]

The angle of incidence for a ray of light passing through the center of curvature of a concave mirror is 0°.

The angle of incidence is the angle between the surface's normal and the incident ray. For a concave mirror, the normal of the surface is along the center of the curvature, and a ray of light passed through a center of curvature passes through the normal of the surface.

The ray of light retreats its path making a zero angle of reflection. The law of reflection state that the angle of incidence is equal to the angle of reflection; therefore, the angle of incidence of a concave surface passed through the center of curvature is zero degrees.

Learn more about the  angle of incidence here:

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8 0
2 years ago
1. A soccer ball is kicked horizontally off a cliff with an initial speed of 8 m/s and lands 16 m from the base of
lana66690 [7]

Answer:

Height of cliff = S = 20 m (Approx)

Explanation:

Given:

Initial velocity = 8 m/s

Distance s = 16 m

Starting acceleration (a) = 0

Computation:

s = ut + 1/2a(t)²

16 = 8t

t = 2 sec

Height of cliff = S

Gravitational acceleration = 10 m/s

S = 1/2a(t)²

S = 1/2(10)(2)²

Height of cliff = S = 20 m (Approx)

3 0
3 years ago
If a ball has a velocity of 18 m/s, how far does it travel in 15 seconds
Stolb23 [73]

Answer:

The answer is

<h2>270 m</h2>

Explanation:

To find the distance when given the velocity and time we use the formula

<h3>distance = velocity × time</h3>

From the question

velocity of the ball = 18 m/s

time = 15 s

So the distance is

distance = 18 × 15

We have the final answer as

<h3>270 m</h3>

Hope this helps you

7 0
3 years ago
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