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Rufina [12.5K]
3 years ago
7

A stuntman of mass 55 kg is to be launched horizontally out of a spring-

Physics
1 answer:
zepelin [54]3 years ago
6 0

Answer:20

Explanation: i konw this stuff

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A boat is leaving the dock. what sound signal should be used to alert others?
DaniilM [7]
Blasts are used for communicating different signals when vessels move.When a boat is leaving, a long blast, at intervals of not more than two minutes, is used for alerting other vessels, when a boat is sailing. When leaving the dock, only a single prolonged blast is used for indicating others, that you are leaving. 
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4 years ago
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What happens to the orbit time as the distance increases.
Maslowich
The orbital period increases if the orbital distance is increased.
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3 years ago
A 50-cm wire placed in an east-west direction is moved horizontally to the north with a speed of 2.0 m/s. the horizontal compone
Strike441 [17]

When a wire is moved inside uniform magnetic field then its free electrons will experience magnetic force on it due to which wire will have potential difference at its ends.

Now here we will have magnetic field due to earth and wire is moving in this constant field so induced emf is given by formula

EMF = v.(B x L)

given that

B = 25\mu Tj - 50\mu Tk

v = 2 m/s j

L = 0.50 m (-i)

now by using the above formula we will have

EMF = 2(j) .(25\mu j - 50\mu k) x (-0.50 i)

EMF = 2(j) .(12.5\mu k + 25\mu j)

EMF = 50 \mu Volts

5 0
3 years ago
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Gasoline burns in the cylinder of an automobile engine. During the combustion reaction, the production of gas forces the piston
serg [7]

Answer:

\Delta U = 1640 J

Explanation:

As we know by first law of thermodynamics that for ideal gas system we have

Heat given = change in internal energy + Work done

so here we will have

Heat given to the system = 2.2 kJ

Q = 2200 J

also we know that work done by the system is given as

W = 560 J

so we have

\Delta U = Q - W

\Delta U = 2200 - 560

\Delta U = 1640 J

6 0
3 years ago
A 100-kg running back runs at 5 m/s into a stationary linebacker. It takes 0.5 s for the running back to be completely stopped.
Elza [17]

Answer:

1000 N

Explanation:

First, we need to find the deceleration of the running back, which is given by:

a=\frac{v-u}{t}

where

v = 0 is his final velocity

u = 5 m/s is his initial velocity

t = 0.5 s is the time taken

Substituting, we have

a=\frac{0-5 m/s}{0.5 s}=-10 m/s^2

And now we can calculate the force exerted on the running back, by using Newton's second law:

F=ma=(100 kg)(-10 m/s^2)=-1000 N

so, the magnitude of the force is 1000 N.

6 0
3 years ago
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