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3 years ago

What is the empirical formula of a compound that contains 27.0% s

Physics

1 answer:

eduard3 years ago

6 0

Answer:

Empirical formula of the compound = SOCl₂

Explanation:

QUESTION:What is the empirical formula of a compound that contains 27.0% S, 13.4% O, and 59.6% Cl by mass?

The empirical formula of a compound is its simplest formula. It tells us

* The component element present in a molecule of the compound.

* The ratio in which these elements are combined together, i.e mole ratio.

To calculate the empirical formula of a compound that contains 27.0% S, 13.4% O, and 59.6% Cl by mass. ( Relative atomic mass of S=32gmol⁻¹, 0=16gmol⁻¹, Cl=35.5gmol⁻¹)

Sulphure S, Oxygen O, Chlorine Cl

percentage by mass: 27.0% 13.4% 59.6%

Step 1:

Divide by their relative

atomic mass: 27.0/32.0 13.4/16.0 59.6/35.5

⇒⇒⇒⇒⇒⇒⇒⇒⇒ 0.844 0.838 1.679

Step 2:

Divide by the

smallest mole ratio: 0.844/0.838 0.838/0.838 1.679/0.838

∴ 1 : 1 : 2.

from the analysis above, the compound contains Sulphur, Oxygen and Chlorine in the ratio of 1:1:2.

∴ Empirical formula of the compound = SOCl₂

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A tree is 24 feet 8 inches tall. What is its height in meters?

Serggg [28]

In meters, that would be 7.4676

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4 years ago

A driver enters a one-lane tunnel at 34.4 m/s. The driver then observes a slow-moving van 154 m ahead travelling (in the same di

navik [9.2K]

Answer:

Ans. B) 22 m/s (the closest to what I have which was 20.16 m/s)

Explanation:

Hi, well, first, we have to find the equations for both, the driver and the van. The first one is moving with constant acceleration (a=-2m/s^2) and the van has no acceletation. Let´s write down both formulas so we can solve this problem.

$X(van)=5.65t+154$

$X(driver)=34.4t+\frac{(-2)t^{2} }{2}$

or by rearanging the drivers equation.

$X(driver)=34.4t+t^{2}$

Now that we have this, let´s equal both equations so we can tell the moment in which both cars crashed.

$X(van)=X(driver)$

$5.65t+154=34.4t-t^{2}$

$0=t^{2} -(34.4-5.65)t+154$ $0=t^{2} -28.75t+154$

To solve this equation we use the following formulas

$t=\frac{-b +\sqrt{b^{2}-4ac } }{2a}$

Where a=1; b=-28.75; c=154

So we get:

$t=\frac{28.75 +\sqrt{(-28.75)^{2}-4(1)(154) } }{2(1)}=21.63s$ $t=\frac{28.75 -\sqrt{(-28.75)^{2}-4(1)(154) } }{2(1)}=7.12s$

At this point, both answers could seem possible, but let´s find the speed of the driver and see if one of them seems ilogic.

$V(driver)=V_{0} +at$ }

$V(driver)=34.4\frac{m}{s} -2\frac{m}{s^{2} } *(7.12s)=20.16\frac{m}{s}$ $V(driver)=34.4\frac{m}{s} -2\frac{m}{s^{2} } *(21.63s)=-8.86\frac{m}{s}$

This means that 21.63s will outcome into a negative speed, for that reason we will not use the value of 21.63s, we use 7.12s and if so, the speed of the driver when he/she hits the van is 20.16m/s, which is closer to answer A).

Best of luck

8 0

3 years ago

What is your weight on Venus, assuming that the acceleration due to gravity on Venus is 8.875 m/s^2 and your mass is 50 kg.

Volgvan

Answer:

Weight on Venus = 443.75 N

Explanation:

Weight of a body is the product of mass and acceleration due to gravity.

So we have

Weight = Mass x Acceleration due to gravity

W = mg

Mass, m = 50 kg

Acceleration due to gravity, g = 8.875 m/s²

W = 50 x 8.875 = 443.75 N

Weight on Venus = 443.75 N

3 0

3 years ago

Read 2 more answers

Two gliders collide on an air track moving in from opposite directions, and they bounce back. The masses of the gliders are 0.20

timurjin [86]

Answer:

so initial momentum is 0.22kgm/s

Explanation:

m1=0.20kg

m2=0.30kg

initial velocity of m1=u1=0.50m/s

initial velocity of m2=u2=0.40m/s

total momentum of the system before collision

Pi=m1u1+m2u2

Pi=0.20kg×0.50m/s+0.30kg×0.40m/s

Pi=0.1kgm/s+0.12kgm/s

Pi=0.22kgm/s

3 0

3 years ago

If an oscillating mass has a frequency of 1.25 Hz, it makes 100 oscillations in

KatRina [158]

Answer:

Time, t = 80 seconds

Explanation:

Given that,

The frequency of the oscillating mass, f = 1.25 Hz

Number of oscillations, n = 100

We need to find the time in which it makes 100 oscillations. We know that the frequency of an object is number of oscillations per unit time. It is given by :

$f=\dfrac{n}{t}$

$t=\dfrac{n}{f}$

$t=\dfrac{100}{1.25\ Hz}$

t = 80 seconds

So, it will make 100 oscillations in 80 seconds. Hence, this is the required solution.

4 0

3 years ago