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3 years ago

What is the empirical formula of a compound that contains 27.0% s

Physics

1 answer:

eduard3 years ago

6 0

Answer:

Empirical formula of the compound = SOCl₂

Explanation:

QUESTION:What is the empirical formula of a compound that contains 27.0% S, 13.4% O, and 59.6% Cl by mass?

The empirical formula of a compound is its simplest formula. It tells us

* The component element present in a molecule of the compound.

* The ratio in which these elements are combined together, i.e mole ratio.

To calculate the empirical formula of a compound that contains 27.0% S, 13.4% O, and 59.6% Cl by mass. ( Relative atomic mass of S=32gmol⁻¹, 0=16gmol⁻¹, Cl=35.5gmol⁻¹)

Sulphure S, Oxygen O, Chlorine Cl

percentage by mass: 27.0% 13.4% 59.6%

Step 1:

Divide by their relative

atomic mass: 27.0/32.0 13.4/16.0 59.6/35.5

⇒⇒⇒⇒⇒⇒⇒⇒⇒ 0.844 0.838 1.679

Step 2:

Divide by the

smallest mole ratio: 0.844/0.838 0.838/0.838 1.679/0.838

∴ 1 : 1 : 2.

from the analysis above, the compound contains Sulphur, Oxygen and Chlorine in the ratio of 1:1:2.

∴ Empirical formula of the compound = SOCl₂

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