So lets fill out what we have first:
Vi or initial velocity = 20 m/s
Acceleration or a = 4 m/s^2
Time for the motion = 10s
Now, using the four main kinematic equations we can deduce that the best kinematic equation to use in these terms is:
Δx = Vi(t) + 0.5at²
Plug all of our information in:
Δx = (20)(10) + (0.5)(4)(100)
Δx = 400 m
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Answer: (2) > (1) > (3) > (4)
Explanation:
(1) a +1 charge and a -1 charge separated by 200 pm:
The potential energy in this case will be,
(2) a +1 charge and a +1 charge separated by 100 pm:
The potential energy in this case will be,
(3) a +1 charge and a -1 charge separated by 100 pm:
The potential energy in this case will be,
(4) a +2 charge and a -1 charge separated by 100 pm:
The potential energy in this case will be,
So, the order from <u>highest</u> potential energy <u>to lowest</u> potential energy is:
(2) > (1) > (3) > (4)
We have 2 journeys , one to school and one to home.
We already have the distance travelled in the first journey .
To find the distance of the second one , we need to find out the time .
Because ,
D= Time x speed
Since have the distance of the first journey , we can find the the time of the second journey .
Using the formula:
Time= D/S
To find the total time :
First:
Convert 20 minutes to hours : 20/60= 0.33 hrs
And add it to 3 (3hrs) = 3+0.33= 3.33hrs
This is our total time .
Second:
To find the time of the first journey , we divide:
130/95= 1.36hrs
(D/S)=T
Since we need the time of the second half, we subtract the time of the first half from the total time travelled:
3.33-1.36= 1.97hrs
And that’s how we found out the time of the second journey (again to find distance).
Now , the last step is to workout the distance travelled at the second journey.
We have the time = 1.97 hrs and the speed = 65 km/h
D=T x S
1.97 x 65= 128.05 km
And that’s your answer.