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Kazeer [188]
3 years ago
8

By how much does the volume of an aluminum cube 4.00 cm on an edge increase when the cube is heated from 19.0°C to 67.0°C? The l

inear expansion coefficient of aluminum is 23.0 x 10^-6 /C°.
Physics
1 answer:
Genrish500 [490]3 years ago
5 0

Answer:

The volume of an aluminum cube is 0.212 cm³.

Explanation:

Given that,

Edge of cube = 4.00 cm

Initial temperature = 19.0°C

Final temperature = 67.0°C

linear expansion coefficient \alpha=23.0\times10^{-6}/C^{\circ}

We need to calculate the volume expansion coefficient

Using formula of  volume expansion coefficient

\beta=3\alpha

Put the value into the formula

\beta=3\times23.0\times10^{-6}

\beta=0.000069=69\times10^{-6}/C^{\circ}

We need to calculate the volume

V= a^3

V=4^3

V=64\ cm^3

The change temperature of the cube is

\Delta T=T_{f}-T_{i}

Put the value into the formula

\Delta T=67-19 = 48^{\circ}C

We need to calculate the increases volume

Using formula of increases volume

\Delta V=V\beta\Delta T

Put the value into the formula

\Delta V=64\times69\times10^{-6}\times48

\Delta V=0.212\ cm^3

Hence, The volume of an aluminum cube is 0.212 cm³.

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aev [14]

Answer:

The mass of 0.02 m³ of gold is 386 kilograms

Explanation:

Given:

The density of the gold = 19300 kg/m³.

The volume of gold = 0.02 m³

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We know that density is mass divided per unit volume.

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Mass = 386 kilograms

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This is not my answer I copied it but hope it helps:)

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Explanation:

Trust me. Im an expert in physics

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