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2 years ago

Is it true or false

Physics

1 answer:

tester [92]2 years ago

8 0

Answer:

false

Explanation:

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A monument has a height of 348 ft, 8 in. Express this height in meters. Answer in units of m.

tensa zangetsu [6.8K]

Answer:

The height of mountain in meter will be 106.2732 m

Explanation:

We have given height of mountain = 348 ft,8 in

We know that 1 feet = 0.3048 meter

So 348 feet $=348\times 0.3048=106.07meter$

And we know that 1 inch = 0.0254 meter

So 8 inch $8\times 0.0254=0.2032m$

So the total height of mountain in meter = 106.07+0.2032 = 106.2732 m

The height of mountain in meter will be 106.2732 m

4 0

3 years ago

What is the wavelength of a 22.75×109Hz radar signal in free space? The speed of light is 2.9979×108m/s. Express your answer to

Romashka-Z-Leto [24]

Answer:

1.318 * 10^(-2) m

Explanation:

Parameters given:

Frequency, f = 22.75 * 10^9 Hz

Velocity, v = 2.9979 * 10^8 m/s

Wavelength is given as:

Wavelength = v/f

Wavelength = (2.9979 * 10^8) / (22.75 * 10^9)

Wavelength = 0.01318 m = 1.318 * 10^(-2) m

8 0

3 years ago

Read 2 more answers

A particle is acted on by two torques about the origin: τ→1 has a magnitude of 8 N·m and is directed in the positive direction o

lyudmila [28]

To give solution to the exercise we must use the concepts of Torque, Vector magnitude and vector direction of the forces.

For the given problem we have to

$T_i = 8Nm$

$T_j = -8.9Nm$

In this way the torque acting on the particle as a function of distance and time is,

$\tau = \frac{dL}{dt} = 8\hat{i}-8.9\hat{j}$

The net torque acting on the particle is

$\tau_{net} = \sqrt{T_i^2+T_j^2}$

$\tau_{net} = \sqrt{(8)^2+(-8.9)^2}$

$\tau_{net} = 11.967Nm$

PART B) The direction of the torque is given by,

$tan\theta = \frac{y}{x}$

$\theta = tan^{-1}\frac{y}{x}$

$\theta = tan^{-1}(\frac{-8.9}{8})$

$\theta = -48.04\°$

Therefore the torque direction is 48.04° below the x axis.

5 0

4 years ago

A dog and a cat sit on a merry-go-round. The dog sits 0.3 m from the center. The cat sits 1.5 m from the center. The whole merry

pochemuha

Answer:

hope that pic helps!! let me know!!

Explanation:

or this expert answers from expert

8 0

3 years ago

Arm ab has a constant angular velocity of 16 rad/s counterclockwise. At the instant when theta = 60

geniusboy [140]

The <em>linear</em> acceleration of collar D when <em>θ = 60°</em> is - 693.867 inches per square second.

<h3>How to determine the angular velocity of a collar</h3>

In this question we have a system formed by three elements, the element AB experiments a <em>pure</em> rotation at <em>constant</em> velocity, the element BD has a <em>general plane</em> motion, which is a combination of rotation and traslation, and the ruff experiments a <em>pure</em> translation.

To determine the <em>linear</em> acceleration of the collar ( $a_{D}$ ), in inches per square second, we need to determine first all <em>linear</em> and <em>angular</em> velocities ( $v_{D}$ , $\omega_{BD}$ ), in inches per second and radians per second, respectively, and later all <em>linear</em> and <em>angular</em> accelerations ( $a_{D}$ , $\alpha_{BD}$ ), the latter in radians per square second.

By definitions of <em>relative</em> velocity and <em>relative</em> acceleration we build the following two systems of <em>linear</em> equations:

<h3>Velocities</h3>

$v_{D} + \omega_{BD}\cdot r_{BD}\cdot \sin \gamma = -\omega_{AB}\cdot r_{AB}\cdot \sin \theta$ (1)

$\omega_{BD}\cdot r_{BD}\cdot \cos \gamma = -\omega_{AB}\cdot r_{AB}\cdot \cos \theta$ (2)

<h3>Accelerations</h3>

$a_{D}+\alpha_{BD}\cdot \sin \gamma = -\omega_{AB}^{2}\cdot r_{AB}\cdot \cos \theta -\alpha_{AB}\cdot r_{AB}\cdot \sin \theta - \omega_{BD}^{2}\cdot r_{BD}\cdot \cos \gamma$ (3)

$-\alpha_{BD}\cdot r_{BD}\cdot \cos \gamma = - \omega_{AB}^{2}\cdot r_{AB}\cdot \sin \theta + \alpha_{AB}\cdot r_{AB}\cdot \cos \theta - \omega_{BD}^{2}\cdot r_{BD}\cdot \sin \gamma$ (4)

If we know that $\theta = 60^{\circ}$ , $\gamma = 19.889^{\circ}$ , $r_{BD} = 10\,in$ , $\omega_{AB} = 16\,\frac{rad}{s}$ , $r_{AB} = 3\,in$ and $\alpha_{AB} = 0\,\frac{rad}{s^{2}}$ , then the solution of the systems of linear equations are, respectively:

<h3>Velocities</h3>

$v_{D}+3.402\cdot \omega_{BD} = -41.569$ (1)

$9.404\cdot \omega_{BD} = -24$ (2)

$v_{D} = -32.887\,\frac{in}{s}$ , $\omega_{BD} = -2.552\,\frac{rad}{s}$

<h3>Accelerations</h3>

$a_{D}+3.402\cdot \alpha_{BD} = -445.242$ (3)

$-9.404\cdot \alpha_{BD} = -687.264$ (4)

$a_{D} = -693.867\,\frac{in}{s^{2}}$ , $\alpha_{BD} = 73.082\,\frac{rad}{s^{2}}$

The <em>linear</em> acceleration of collar D when <em>θ = 60°</em> is - 693.867 inches per square second. $\blacksquare$

<h3>Remark</h3>

The statement is incomplete and figure is missing, complete form is introduced below:

<em>Arm AB has a constant angular velocity of 16 radians per second counterclockwise. At the instant when θ = 60°, determine the acceleration of collar D.</em>

To learn more on kinematics, we kindly invite to check this verified question: brainly.com/question/27126557

5 0

2 years ago