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max2010maxim [7]
2 years ago
12

Is it true or false

Physics
1 answer:
tester [92]2 years ago
8 0

Answer:

false

Explanation:

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A wire 50 cm long with an east-west orientation carries a current of 7.0 A eastward. There is a uniform magnetic field perpendic
konstantin123 [22]

Answer:

The magnetic field is 0.143 T in north direction.

Explanation:

Given that,

Length = 50 cm

Current = 7.0 A

Force = 0.5 N

We need to calculate the magnetic field

Using formula of magnetic force

\vec{F}I\vec{L}\times\vec{B}

F=ILB

B=\dfrac{F}{IL}

B=\dfrac{0.5}{7.0\times50\times10^{-2}}

B=0.143\ T

The direction of the magnetic field toward north.

Hence, The magnetic field is 0.143 T in north direction.

3 0
3 years ago
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Why will a struck tuning fork sound louder when it is held against a table?.
QveST [7]

Answer:
1.)the surface of the table is set into vibration
2.)the initial vibration was larger
3.)The entire table vibrates

Explanation:<u><em>hope this helps :3 have a good day xlXCherryColaXlx..(pls mark me brainliest)</em></u>

7 0
2 years ago
starting from rest , a formula one car accelerates uniformly at 25m\s2 for 30secs. what distance does it cover in the last one s
Anestetic [448]

The distance covered in the last second of motion is 737.5 m

Explanation:

The motion of the car is a uniformly accelerated motion, so we can use the suvat equations.

First of all, we have to find the velocity of the car when the last second of motion starts, that is the velocity of the car after t = 29 s. We can use the equation:

v = u + at

where

u = 0 is the initial velocity

a=25 m/s^2 is the acceleration

Substituting t = 29 s,

v=0+(25)(29)=725 m/s

Now we can find the distance covered in the last second of motion by using

s=ut+\frac{1}{2}at^2

where

u = 725 m/s is the velocity at the beginning of the last second

t = 1 s is the time interval considered

a=25 m/s^2 is the acceleration

Substituting,

s=(725)(1)+\frac{1}{2}(25)(1)^2=737.5 m

Note that the acceleration of 25 m/s^2 is not realistic for a car, but I still have used the data of the problem.

Learn more about acceleration:

brainly.com/question/9527152

brainly.com/question/11181826

brainly.com/question/2506873

brainly.com/question/2562700

#LearnwithBrainly

6 0
3 years ago
A 2.0 x 10^3-kilogram car travels at a constant speed of 12 meters per second around a circular curve of radius 30. meters. What
Vikentia [17]

The magnitude of the centripetal acceleration of the car as it goes round the curve is 4.8 m/s²

<h3>Circular motion</h3>

From the question, we are to determine the magnitude of the centripetal acceleration.

Centripetal acceleration can be calculated by using the formula

a_{c} =\frac{v^{2} }{r}

Where a_{c} is the centripetal acceleration

v is the velocity

and r is the radius

From the given information

v = 12 \ m/s

and r = 30 \ m

Therefore,

a_{c} =\frac{12^{2} }{30}

a_{c} =\frac{144 }{30}

a_{c} = 4.8\ m/s^{2}

Hence, the magnitude of the centripetal acceleration of the car as it goes round the curve is 4.8 m/s²

Learn more on circular motion here: brainly.com/question/20905151

4 0
2 years ago
A family pool holds 10,000 gallons of water how many cubic meters is this
ruslelena [56]
4959167 is how many cubic meters in 10,000 gallons of water
3 0
4 years ago
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