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ololo11 [35]
3 years ago
12

A jogger runs 6 km north, 5 km east, then another 4 km north. Her average speed 8 km/h. How long will it take her to complete he

r run?10.
Using the information from the previous question, what is her average velocity during this time?
Physics
1 answer:
34kurt3 years ago
3 0

Answer:

The time taken to complete her run is 1.9 hr.

Explanation:

Speed is a scalar quantity and it is defined as the ratio of distance covered to the time taken to cover that distance. As distance is also a scalar quantity, so the directions given in the problem can be ignored. Thus, the distance covered by the jogger is the sum of kilometers given in problem.

Distance covered = 6+5+4 = 15 km

And the speed is given as 8 km/hr.

So the time taken will be ratio of distance to speed.

So the jogger will take 1.9 hr to complete her run.

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Part of one row of the periodic table is shown. 4 blue boxes in a row. The first has S n at the center and 50 above with tin and
nydimaria [60]

Answer:

Atoms of tellurium (Te) have the greatest average number of neutrons equal to 76.

Explanation:

In the periodic table, Elements are represented with their respected symbols. Above the symbol is the elements atomic number which is equal to the number of protons in each atom. Below the symbol is the mass number of that element which is roughly equal to the sum of neutrons and protons of that atom.

To calculate the number of neutrons we can take the difference of Atomic number and mass number:

Number of neutrons = mass number - atomic number

<u>- Tin:</u>

Atomic number = 50

Mass number = 119

Number of neutrons = mass number - atomic number = 119 - 50

Number of neutrons = 69

<u>- Antimony(Sb):</u>

Atomic number = 51

Mass number = 122

Number of neutrons = mass number - atomic number = 122 - 51

Number of neutrons = 71

<u>- Tellurium(Te):</u>

Atomic number = 52

Mass number = 128

Number of neutrons = mass number - atomic number = 128 - 52

Number of neutrons = <u>76</u>

<u>- Iodine(I):</u>

Atomic number = 53

Mass number = 127

Number of neutrons = mass number - atomic number = 127 - 53

Number of neutrons = 74

Here, the greatest number of neutrons is for the atoms of Tellurium(Te).

7 0
3 years ago
Read 2 more answers
Explain why engineers leave a gap in a concrete bridge (answer must relate to density)
seraphim [82]
<span>Different materials expand and contract at different rates based on temperature. Just like if you leave a plastic bottle full of water in a freezer it will burst, but if you leave it partially full no problem.....Ok?Expansion joints do the same for bridges. There is a gap to allow for temperature related expansions and contractions. Sometimes you drive over bridges and roadways where this movement is constricted and you might notice a bumpy ride. Engineers can predict the variation of structural length based on span lengths and leave the necessary gaps.....btw, NICE QUESTION:)</span>


6 0
3 years ago
The activity of a radioisotope is found to decrease 40% of its original value in 2.59 x 10 s.
Rainbow [258]

Answer: 0.0353\ s^{-1}

Explanation:

Given

Radioactive material is found to decrease 40% of its original value in 2.59\times 10\ s

Sample at any time is given by

N=N_oe^{-\lambda t}

where, \lambda=\text{decay constant}

Put values

\Rightarrow 0.4N_o=N_oe^{-\lambda\cdot 2.59\times 10}\\\Rightarrow 0.4=e^{-\lambda\cdot 2.59\times 10

Taking natural logarithm both side

\Rightarrow \lambda=\dfrac{\ln 2.5}{25.9}\\\\\Rightarrow \lambda =0.0353\ s^{-1}

8 0
3 years ago
Which is a compound<br> A Kr<br> B O<br> 2<br><br> c cl2<br> d CuF2
Volgvan
I think the answer is CuF2
7 0
3 years ago
A red blood cell contains 4.8 107 free electrons. What is the total charge of these electrons in the red blood cell?
tatuchka [14]

Answer:

Charge, q=7.68\times 10^{-12}\ C

Explanation:

It is given that,

The number of electron in a RBCs, n=4.8\times 10^7

We need to find the total charge of these electrons in the red blood cell. Let it is q. Using the quantization of charge as follows :

q = ne

e is the change on electron

q=4.8\times 10^7\times 1.6\times 10^{-19}\\\\q=7.68\times 10^{-12}\ C

So, the net charge is 7.68\times 10^{-12}\ C.

7 0
3 years ago
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