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3 years ago

Please type a three paragraph essay (5-7 sentences per paragraph), and the essay should include the following things:

1 answer:

4 0

When I designed my vessel I knew inertia would cause the egg to continue to want to fall. I also knew that it would not accelerate at a great speed so I had to create a vessel that would contract and adjust easily. That's why I used a sponge and cotton to soften the impact of the egg. Then I simply held it together with a rubber band. With this construction I was able to build a vessel that safely carried my egg.

The stored energy in this contraption seemed to lie at the sponge. Were when I picked it up and threw it, I knew that the sponge was more dense then the egg so there was a lot of potential energy waiting to squash the sponge. Of course there was a lot of kinetic energy as I threw it into the air so I didn't throw it to high into the air otherwise the vessels acceleration falling down would have been a higher speed, resulting into a possible catastrophic event. So the mechanical energy was evenly distributed. I used Newton's first law of motion, inertia, to create a vessel that would save the egg from destruction due to inertia.

We use potential and kinetic knowledge to determine whether a car could drive up a hill or how fast a ball would roll down my driveway. Both of these ways represent physics and how we use this to solve equations. All though these questions probably don't get asked by kids. It's important to know that when designing contraptions like cars or even swimming flippers, you need to know how much kinetic or potential energy will be available.

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An aluminum cup of 150 cm3 capacity is completely filled with glycerin at 23°C. How much glycerin will spill out of the cup if t

AVprozaik [17]

Answer:

1.19cm^3 of glycerine

Explanation:

Let Vo= 150cm^3 for both aluminum and glycerine, using expansion formula:

Volume of spill glycerine = change in volume of glycerine - change in volume of aluminum

Volume of glycerine = coefficient of volume expansion of glycerine * Vo* change in temperature - coefficient of volume expansion of Aluminum*Vo* change temperature

coefficient of volume expansion of aluminum = coefficient of linear expansion of aluminum*3 = 23*10^-6 * 3 = 0.69*10^-4 oC^-1

Change in temperature = 41-23 = 18oC

Volume of glycerine that spill = (5.1*10^-4) - (0.69*10^-4) (150*18) = 4.41*10^-4*2700 = 1.19cm3

3 0

3 years ago

A teacher discusses a scientific theory that has been in place for almost a century. which would present the greatest challenge

Umnica [9.8K]

Answer: The theory might have become Obsolete or Superseded

Explanation:

A theory becomes obsolete or superseded if it becomes inadequate, false or incomplete in how its describes reality. It does not matter if it was once accepted. There are some theories such as Lysenkoism that are currently described as being obsolete because it does not conform to current reality. Another example of a theory that was superseded is the phlogiston theory. It was replaced a different theory of energy.

3 0

3 years ago

Read 2 more answers

The horizontal beam in Fig. E11.14 weighs 190 N, and its center of gravity is at its center. Find (a) the tension in the cable a

grandymaker [24]

Answer:

(a). The tension in the cable is 658.33 N.

(b). The horizontal components of the force exerted on the beam at the wall is 526.66 N.

(c). The vertical components of the force exerted on the beam at the wall is 95.002 N.

Explanation:

Given that,

Weight of beam= 190 N

Here, The center of gravity is at its center

According to figure,

The angle is

$\sin\theta=\dfrac{3}{5}$

The horizontal component is

$T_{x}=T\cos\theta$

The vertical component is

$T_{y}=T\sin\theta$

(a). We need to calculate the tension in the cable

Using formula of net torque acting on the pivot

$\sum\tau=F_{b}\times r+F_{w}\times r'-T\sin \theta\times r'$

Put the value into the formula

$0=190\times2+300\times 4-T\sin\theta\times 4$

$T\sin\theta\times 4=380+1200$

$T=\dfrac{1580\times5}{3\times 4}$

$T=658.33\ N$

(b). We need to calculate the horizontal components of the force exerted on the beam at the wall

Using formula of horizontal component

$F_{x}=T\cos\theta$

Put the value into the formula

$F_{x}=658.33\times\dfrac{4}{5}$

$F_{x}=526.66\ N$

(c). We need to calculate the vertical components of the force exerted on the beam at the wall

Using formula of vertical component

$F_{y}=F_{b}+F_{w}-T\sin\theta$

Put the value into the formula

$F_{y}=190+300-658.33\times\dfrac{3}{5}$

$F_{y}=95.002\ N$

Hence, (a). The tension in the cable is 658.33 N.

(b). The horizontal components of the force exerted on the beam at the wall is 526.66 N.

(c). The vertical components of the force exerted on the beam at the wall is 95.002 N.

3 0

3 years ago

Look at the circuit diagram. Which of these components is part of the circuit?

Roman55 [17]

Answer:

b ac power source

Explanation:

ieififuffucjcjcicogore8e8e9e9e9e9ew0ww0w0w

7 0

3 years ago

what is the potential energy of the ball when it gets to its maximum height just before falling back to the ground

love history [14]

Answer:

I will say that the the potential energy will be at its maximum.

Explanation:

potential energy deals with gravity and gravity deals with height, so when a object is in its maximum height it will have the maximum potential energy.

6 0

3 years ago