Explanation:
The volume of a simple compressible system is not fixed. At a state of equilibrium, there should be uniformity in the entire system.
From the question we have here, these are the correct options:
1. It cannot be a mixture of different substances (e.g. oxygen and nitrogent)
2. It can be composed of any phases of a substance: solid, liquid, and/or gas
3. It's state is specified if given two independent, intensive thermodynamic properties.
Answer:
2 m/s
Explanation:
From the conservation of momentum, the initial momentum of the system must be equal to the final momentum of the system.
Let the 10.00 kg mass be 
and the 12.0 kg mass be 
. When they collide and stick, they have a combined mass of 
.
Momentum is given by 
. Set up the following equation:
, where 
is the desired final velocity of the masses.
Call the right direction positive. To indicate the 12.0 kg object is travelling left, its velocity should be substitute as -8.00 m/s.
Solving yields:
Answer:
The correct answer is C.
Clarify any confusing information in the instructions.
Explanation:
The very first thing that we need before conducting a scientific investigation is a set of instructions which might include the following information:
-What we are experimenting on?
-How are we going to do it?
-What things are needed for it?
If there are any confusions in the instructions, the chances of making a mistake rises. So, it is very important to clarify the confusions found in the instructions before choosing things needed for the experiment and starting the experiment.
Below are the examples of work being done on an object
Carrying a box up a flight of stairs.
Lifting a bag of groceries.
Lifting a rock off the ground.
Pushing a grocery cart through the store.
<h3>Workdone</h3>
Work is said to be done when a force applied moves a distance
Work done = force × distance
Learn more about work done:
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For a total charge of Q coulomb is uniformly distributed along a rod 40cm in length, the electric field intensity 20cm away from the rod is mathematically given as
E1=1.598*10^11v/m
<h3>What is the e
lectric field intensity 20cm away from the
rod along its perpendicular
bisector?</h3>
Generally, the equation for the initial electric field intensity is mathematically given as
Therefore
Hence
E1=B*9*10^{13})/(10*110)*
E1=1.598*10^11v/m
In conclusion, the electric field intensity
E1=1.598*10^11v/m
Read more about Electric field
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