Answer:
Explanation:
Consider another special case in which the inclined plane is vertical (θ=π/2). In this case, for what value of m1 would the acceleration of the two blocks be equal to zero
F - Force
T = Tension
m = mass
a = acceleration
g = gravitational force
Let the given Normal on block 2 = N
and 
and the tension in the given string is said to be 
When the acceleration 
for the said block 1.
It will definite be zero only when Force is zero , F=0.
Here by Force, F
I refer net force on block 1.
Now we know
It is known that if the said
,
then Tension 
![[since \sin(\pi/2) = 1]](https://tex.z-dn.net/?f=%5Bsince%20%5Csin%28%5Cpi%2F2%29%20%3D%201%5D)
,
Now making 
So If we are to make Force equal to zero
Answer:
828 kg/m³ or 0.828 g/cm³
Explanation:
Applying,
D = m/V............. Equation 1
Where D = density of the liquid, m = mass of the liquid, V = volume of the liquid.
From the question,
Given: m = 77 g , V = 93 cm³
Substitute these values into equation 1
D = 77/93
D = 0.828 g/cm³
Converting to kg/m³
D = 828 kg/m³
Rubber band, elastic, spring
Answer:
1
2
The distance is 
Explanation:
From the question we are told that
The maximum speed of the cheetah is 
The maximum of gazelle is 
The distance ahead is 
Let 
denote the time which the cheetah catches the gazelle
Gnerally the equation representing the distance the cheetah needs to move in order to catch the gazelle is
=> 
=> 
=>
Now at t = 7.5 s
=> 
=> 
=>
Hence the for the gazelle to escape the cheetah it must be 55.2 m
