Answer: 10.3m/s
Explanation:
In theory and for a constant velocity the physics expression states that:
Eq(1): distance = velocity times time <=> d = v*t for v=constant.
If we solve Eq (1) for the velocity (v) we obtain:
Eq(2): velocity = distance divided by time <=> v = d/t
Substituting the known values for t=15s and d=155m we get:
v = 155 / 15 <=> v = 10.3
The frequency of the wave is 6800 Hz
<u>Explanation:</u>
Given:
Wave number, n = 20
Speed of light, v = 340 m/s
Frequency, f = ?
we know:
wave number = 
Therefore, the frequency of the wave is 6800 Hz
Answer:
(a) The angle of projection is 63 degree.
(b) The velocity of projection is 24.5 m/s.
Explanation:
Height, h = 1 m
horizontal distance, d = 50 m
time, t = 4.5 s
Let the initial velocity is u and the angle is A.
(a) Horizontal distance = horizontal velocity x time
50 = u cos A x 4.5
u cos A = 11.1 .....(1)
Use second equation of motion in vertical direction
Divide (2) by (1)
tan A = 1.97
A = 63 degree
(b) Substitute the value of A in equation (2)
u x sin 63 = 21.8
u = 24.5 m/s
Answer:
a) the frequency of the wave is 0.2 Hz
b) the speed of the wave 4 m/s
Explanation:
Given that;
time period = to complete one cycle t = 5 sec
frequency f = 1/t
frequency f = 1 / 5sec
f = 0.2 Hz
Therefore the frequency of the wave is 0.2 Hz
b)
speed of wave V = λf
given that our wavelength is 20.0 m
we substitute
speed of wave V = 20.0 × 0.2
speed of wave V = 4 m/s
Therefore, the speed of the wave 4 m/s
Here’s a good photo to reference when converting in the metric system.
Each time you move down a step you move the decimal to the right, each time you move up a step you move the decimal to the left.
We are going from 1.2 kg or kilograms, which is at the very top left of the ladder. To get to mg or milligrams, we would have to make six jumps, so we’d move the decimal over six times.
1.2 > 12. > 120. > 1200. > 12000. > 120000. > 1200000.
So our final answer would be 1,200,000mg.
