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o-na [289]
3 years ago
7

Consider the reaction below. 2H2O 2H2 + O2 How many moles of hydrogen are produced when 6.28 mol of oxygen form?

Chemistry
1 answer:
g100num [7]3 years ago
8 0

6.28 mol O2 × 2 mol h2 / 1 mol 02 = 12.56 moles h2

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Need help FAST! Will rate 5
evablogger [386]

If 28.4 g of HgO decomposes and produces 2.0 g of oxygen, then 26 grams of Hg is produced.

<h3>What is decomposition reaction?</h3>

Decomposition reactions occur when complex chemical entities split apart into smaller components. Decomposition reactions often demand energy input.

There are three different kinds of breakdown reactions: thermal, photolytic, and electrolytic.

Mass_{reactant = Mass_{product}

Mass_{mercury oxide = Mass_{mercury} + mass_{oxygen}

28g =        mass_{mercury} + 2g

   mass_{mercury} = 26g

Thus, 28.4 g of HgO decomposes and produces 2.0 g of oxygen, then 26 grams of Hg is produced.

percentage mass_{mercury} = \frac{mass_{mercury}}{mass_{mercury}oxide}  X 100%

= 26g/28g

= 93%

thus  93% is the percent by mass of Hg present in HgO.

To learn more about Decomposition reaction, refer to the below link:

brainly.com/question/14112196

# SPJ1

4 0
1 year ago
The first question is the one I need help with
aleksandr82 [10.1K]

I looked at the question and there isn't a lot of information. im assuming the answer is carbon dioxide. its the only substance that would make sense I hope it helps.


5 0
3 years ago
Which must an animal do in order for cellular respiration to begin?
KatRina [158]

Answer:

Eat food

Explanation:

Food contain protein, carbohydrates, fats etc. These nutrients undergoes metabolic process and produced energy in cellular respiration.

There are two types of respiration:

1. Aerobic respiration  

2. Anaerobic respiration

Aerobic respiration

It is the breakdown of glucose molecule in the presence of oxygen to yield large amount of energy. Water and carbon dioxide are also produced as a byproduct.

Glucose + oxygen → carbon dioxide + water + 38ATP

Anaerobic Respiration

It is the breakdown of glucose molecule in the absence of oxygen and produce small amount of energy. Alcohol or lactic acid and carbon dioxide are also produced as byproducts.  

Glucose→ lactic acid/alcohol + 2ATP + carbon dioxide

This process use respiratory electron transport chain as electron acceptor instead of oxygen. It is mostly occur in prokaryotes. Its main advantage is that it produce energy (ATP) very quickly as compared to aerobic respiration.  

5 0
3 years ago
Read 2 more answers
What are the chemical properties of kevlar
Gnesinka [82]

Answer:

<h2>Kevlar has unique properties such as:</h2><h2><em>High tensile strength</em>, <em>high toughness</em>, and <em>chemical stability </em>at high temperatures<em> </em>in polyamides (polymer with repeating unit links by amide bonds.) </h2><h3>~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~</h3>

Δ What is Kelvar? Δ

~ Kevlar is a heat-resistant and strong synthetic fiber

~ Kevlar is widely used as a friction material in the automotive industry, and a combustion protection material in the aerospace industry. <em>~Looked that up!</em>

<h3>~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~</h3>

<em>Hope I helped!!!</em>

<em>GL :)</em>

5 0
3 years ago
The equilibrium constant for the reaction
FinnZ [79.3K]

Answer: The concentrations of Cl_2 at equilibrium is 0.023 M

Explanation:

Moles of  Cl_2 = \frac{\text {given mass}}{\text {Molar mass}}=\frac{10g}{71g/mol}=0.14mol

Volume of solution = 1 L

Initial concentration of Cl_2 = \frac{0.14mol}{1L}=0.14M

The given balanced equilibrium reaction is,

                            COCl_2(g)\rightleftharpoons CO(g)+Cl_2(g)

Initial conc.           0.14 M           0 M       0M    

At eqm. conc.     (0.14-x) M        (x) M        (x) M

The expression for equilibrium constant for this reaction will be,

K_c=\frac{[CO]\times [Cl_2]}{[COCl_2]}

Now put all the given values in this expression, we get :

4.63\times 10^{-3}=\frac{x)^2}{(0.14-x)}

By solving the term 'x', we get :

x = 0.023 M

Thus, the concentrations of Cl_2 at equilibrium is 0.023 M

7 0
3 years ago
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