The molarity of the NaOH solution is 0.03 M
We'll begin by calculating the mole of the KHP
- Mass = 0.212 g
- Molar mass = 204.22 g/mol
- Mole of KHP =?
Mole = mass /molar mass
Mole of KHP = 0.212 / 204.22
Mole of KHP = 0.001 mole
Next, we shall determine the molarity of the KHP solution
- Mole of KHP = 0.001 mole
- Volume = 50 mL = 50/1000 = 0.05 L
- Molarity of KHP =?
Molarity = mole / Volume
Molarity of KHP = 0.001 / 0.05
Molarity of KHP = 0.02 M
Finally , we shall determine the molarity of the NaOH solution
KHP + NaOH —> NaPK + H₂O
From the balanced equation above,
- The mole ratio of the acid, KHP (nA) = 1
- The mole ratio of base, NaOH (nB) = 1
From the question given above, the following data were obtained:
- Volume of acid, KHP (Va) = 50 mL
- Molarity of acid, KHP (Ma) = 0.02 M.
- Volume of base, NaOH (Vb) = 35 mL
- Molarity of base, NaOH (Mb) =?
MaVa / MbVb = nA / nB
(0.02 × 50) / (Mb × 35) = 1
1 / (Mb × 35) = 1
Cross multiply
Mb × 35 = 1
Divide both side by 35
Mb = 1 / 35
Mb = 0.03 M
Thus, the molarity of the NaOH solution is 0.03 M
Complete question:
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Learn more about titration: brainly.com/question/25866669
Answer:
Wavelength of radiation is 0.375×10⁻⁶ m
Explanation:
Given data:
Frequency of radiation = 8.0×10¹⁴ Hz
Wavelength of radiation = ?
Solution:
Frequency and wavelength of lights are inversely proportional to each other.
The wave of light having highest frequency have shortest wavelength and the light with the shortest frequency having highest wavelength.
Formula:
Speed of light = wavelength × frequency
c = λ × f
λ = c/f
This formula shows that both are inversely related to each other.
The speed of light is 3×10⁸ m/s
Frequency is taken in Hz.
It is the number of oscillations, wave of light make in one second.
Wavelength is designated as "λ" and it is the measured in meter. It is the distance between the two crust of two trough.
Now we will put the values in formula.
λ = 3×10⁸ m/s / 8.0×10¹⁴ Hz
λ = 0.375×10⁻⁶ m
Answer:
4.1 atm = 3,116 mmHg = 415.4 kPa
Explanation:
According to Boyle's law, as volume is increased the pressure of the gas is decreased. That can be expressed as:
P₁ x V₁= P₂ x V₂
Where P₁ and V₁ are the initial pressure and volume respectively, and P₂ and V₂ are final pressure and volume, respectively.
From the problem, we have:
V₁= 50.0 L
V₂= 68.0 L
P₂= 3.0 atm
Thus, we calculate the initial pressure as follows:
P₁= (P₂ x V₂)/V₁= (3.0 atm x 68.0 L)/(50.0 L)= 4.08 atm ≅ 4.1 atm
To transform to mmHg, we know that 1 atm= 760 mmHg:
4.1 atm x 760 mmHg/1 atm = 3,116 mmHg
To transform to kPa we use: 1 atm= 101.325 kPa
4.1 atm x 101.325 kPa = 415.4 kPa
I’m pretty sure the immediate answer is 2. Using the equation 60N=(30kg)x2(whatever unit of measure) also it will change because if you change the mass or the Net Force, your going to have to redo the equation based on the new information.
Longer, this is because the H in HNO2 is bonded with an oxygen, no longer allowing this structure to have a resonance structure.
NO2 on the other hand has one double bond and one single bond, so it has a resonance structure. And resonance structures are actually one structure so there isn't really a single and double bond, it's actually a 1 and 1/2 bond that calls for a higher bond order.
And I higher bond order will result in a shorter lengths!
I hope this helps out!!! And just out of curiosity, is this off of an AP FRQ packet??
